Completed question:
In the game of tic-tac-toe, if all moves are performed randomly the probability that the game will end in a draw is 0.127. Suppose six random games of tic-tac-toe are played. What is the probability that at least one of them will end in a draw?
Answer:
0.557
Step-by-step explanation:
For each game, the probability of not end in a draw is 1 - 0.127 = 0.873. Thus, because each game is independent of each other, the probability of all of them not end in a draw is the multiplication of the probability of each one:
0.873x0.873x0.873x...x0.873 = 0.873⁶ = 0.443
Thus, the probability that at least one of them end in a draw is the total probability (1) less the probability that none of them en in a draw:
1 - 0.443
0.557
Answer:
44 units length
Step-by-step explanation:
The side splitter theorem states that if a line is parallel to a side of a triangle and the line intersects the other two sides, then this line divides those two sides proportionally. Therefore:
20/10 = x/22
20/10*22 = x
44 = x
Answer:
distribute the 2 on the left side to become 2(x+7)-->2x+14=-4x+14, add 4x to both sides to become 2x+14+4x=-4x+14+4x-->6x+14=14, subtract 14 from both sides 6x+14-14=14-14-->6x=0 and divide both sides of the equation by 6 to get x alone, 6x/6=0/6-->x=0 so x would equal 0.
Step-by-step explanation:
42-x=58
or, -x=58-42
with change in side sign also chamges we change sides to make like terms in one side and unlike in amother side.
or, -x= 16
or,x=-16.
therefore x=-16...
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>
