Probability that both roads from a to b are blocked is the product of the individual probabilities, i.e.
P(~ab)=0.25*0.25=0.0625
Similarly
P(~bc)=0.25*0.25=0.0625
Probability that EITHER one or both of ab and bc are blocked is the sum of the probabilities:
P(~ab ∪ ~bc)=0.0625+0.0625=0.125
(recall that one cannot travel from a to c if either ab or bc is blocked.)
Therefore the probability that there exists an open route from a to c
= P(ac) = 1-P(~ab ∪ ~bc)
= 1 - 0.125
=0.875
-4 + -3 = -7 Hope this helps!
Step-by-step explanation:
common factor 8 and 18 is 2.
If you subtract 617 and 385 it will give you the answer which is 232 the plane did 232 in the morning than in the afternoon
Hope it helps :)
