HELP. Need help on this

Mathematics

1 answer:

pishuonlain [190]2 years ago

3 0

Answer:

what are the answers

Step-by-step explanation:

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A square with sides x ft long has a perimeter of 34 1/2 ft. How long are the sides of the square

scoundrel [369]

Answer:

8.625 ft for each side.

Step-by-step explanation:

This one's pretty simple. It's a square, so all of its sides are the same length. It's perimeter is given as 34.5 ft, so all you have to do is divide 34.5 by 4 since squares have 4 sides. 34.5/4 is 8.625, which, rounding to the nearest 1/100th, is 8.63. Rounding to the nearest 1/10th it's 8.6, and rounding to the nearest 1th is 9 (although i doubt saying 1th is right, but just because).

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Okay so we have this question of the week thing and this week our answer is 8 so i need a algebra problem that is a two step equ

Inessa05 [86]

Answer:

2x+4=8

x=2

2 times 2 equals 4

Four plus four is 8

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What is the following number in the sequence? What is the sequence's equation?<br> 9, 15, 21, 27, __

fenix001 [56]

Its going up by 6, the answer is 33

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3 years ago

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). what is the perimeter and area in square units

ad-work [718]

Check the picture below.

the triangle has that base and that height, recall that A = 1/2 bh.

now as for the perimeter, you can pretty much count the units off the grid for the segment CB, so let's just find the lengths of AC and AB,

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&C&(~ 6 &,& 2~)
\end{array}~~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AC=\sqrt{(6-2)^2+(2-8)^2}\implies AC=\sqrt{4^2+(-6)^2}
\\\\\\
AC=\sqrt{16+36}\implies AC=\sqrt{52}\implies AC=\sqrt{4\cdot 13}
\\\\\\
AC=\sqrt{2^2\cdot 13}\implies AC=2\sqrt{13}$

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&A&(~ 2 &,& 8~) 
% (c,d)
&B&(~ 16 &,& 2~)
\end{array}\\\\\\
AB=\sqrt{(16-2)^2+(2-8)^2}\implies AB=\sqrt{14^2+(-6)^2}
\\\\\\
AB=\sqrt{196+36}\implies AB=\sqrt{232}\implies AB=\sqrt{4\cdot 58}
\\\\\\
AB=\sqrt{2^2\cdot 58}\implies AB=2\sqrt{58}$

so, add AC + AB + CB, and that's the perimeter of the triangle.

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3 years ago

Write a cosine function for the graph

Whitepunk [10]

the answer is c,

$y = 2 \cos(4x)$

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