Answer: yes they are
Example: if you don’t believe me check for yourself :)
Answer:
there is no greatest load
Step-by-step explanation:
Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:
x ≥ y +600 . . . . . my truck can carry at least 600 pounds more
x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers
Combining these two inequalities, we have ...
4/3y ≥ x ≥ y +600
1/3y ≥ 600 . . . . . . . subtract y
y ≥ 1800 . . . . . . . . multiply by 3
My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.
1. Factor out the greatest common factor (GCF). (There will not always be one).
2. Count the number of terms.
3. Check to be sure each factor is prime, if not, repeat 1-3.
4. Check by multiplying the factors out to see if you get the original polynomial.
112 / 2 = 56
56 x 3 = 168
168 / 16 (16 Oz. in a lbs.) = 10.5 or 10 1/2
A case weighs 10.5 lbs
Answer: 7
Step-by-step explanation:
