Answer:
The ratio of the drag coefficients
is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model,
= The drag coefficient of the prototype, 
The medium of the test for the model,
= The medium of the test for the prototype, 
The drag force is given as follows;

We have;

Therefore;







= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients
≈ 0.0002.
Answer:
3 TIMES 5
Step-by-step explanation:
Answer:
105
Step-by-step explanation:
l is parallel m so angle 3+angle 6=180
Answer:
16.5 =x
Step-by-step explanation:
Since this is a right triangle, we can us trig functions
tan theta = opp side / adjacent
tan 70 = x /6
Multiply each side by 6
6 tan 70 = x
16.48486452 =x
To the nearest tenth
16.5 =x