CscA = 1/sinA
CosACscA = cosA × 1/sinA = cosA/SinA = cotA
Answer: 271
Step-by-step explanation:
The formula we use to find the sample size is given by :-

, where
is the two-tailed z-value for significance level of 
p = prior estimation of the proportion
E = Margin of error.
If prior estimation of the proportion is unknown, then we take p= 0.5 , the formula becomes


Given : Margin of error : E= 0.05
Confidence level = 90%
Significance level 
Using z-value table , Two-tailed z-value for significance level of 

Then, the required sample size would be :

Simplify,

Hence, the required minimum sample size =271
a. 3^4 which is equal to (3^-3)(3^7)
Answer:
The sum of the first 6 terms is 3,412.5.
Step-by-step explanation:
The second term of the geometric series is given by:

Where a1 is the first term and r is the common ratio. The seventh term can be written as a function of the second term as follows:
![a_{7}=a_{1}*r^{6} \\a_{7}=a_{2}*r^{5} \\10,240 = 10*r^{5}\\r=\sqrt[5]{1024} \\r = 4](https://tex.z-dn.net/?f=a_%7B7%7D%3Da_%7B1%7D%2Ar%5E%7B6%7D%20%5C%5Ca_%7B7%7D%3Da_%7B2%7D%2Ar%5E%7B5%7D%20%5C%5C10%2C240%20%3D%2010%2Ar%5E%7B5%7D%5C%5Cr%3D%5Csqrt%5B5%5D%7B1024%7D%20%5C%5Cr%20%3D%204)
The sum of "n" terms of a geometric series is given by:

The sum of the first 6 terms is 3,412.5.
Answer: Heat rejected=150000MW
Heat rate= 2.5
Step-by-step explanation:
Thermal efficiency is defined as work out divided by heat in.
Therefore
thermal efficiency = 40/100= 100000 MW/Heat in
Heat in = 250000MW
For a closed system undergoing a cycle the change in internal energy is zero. Therefore the work out of the system is equal to the net heat transfer of the system. Therefore
Work out= heat in - heat out
Therefore heat out = heat in - work out
Heat out = 250000 MW - 100000MW = 150000 MW which is the amount of heat rejected
The heat rate is defined as the inverse of the thermal efficiency expressed in kJ/kWh.Therefore
Heat rate = 1/thermal efficiency
Heat rate = 1/0.4 = 2.5 kJ/kWh