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Nonamiya [84]
3 years ago
14

Luis had 4 boxes of party favors. One full box contained 16 bags of favors and each bag had 5 items in it. What is the total num

ber
items that Luis had in his possession?
O A. 360
B. 320
O C. 170
OD. 7.5
Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0
The answer is B. 320. 64 bags times 5 items in each bag.
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The typical level of a low tide at a beach is the 0 point on a number line
juin [17]

Answer:

The low tide level is 0, integer as 0

Step-by-step explanation:

The tide is at the numberline point 0, making it at integer 0.

Please let me know if I need to change the answer via comments (pls don't report me)

5 0
3 years ago
Median of 12,13,19,16,32,15,13
Katena32 [7]
We will first put this data in ascending order
12,13,13,15,16,19,32
We then center in on the middle number, we first can “mark out” the highest and lowest number and repeat until we have one number left

12,13,13,15,16,19,32

13,13,15,16,19

13,15,16

The median is 15
3 0
2 years ago
Read 2 more answers
Are the set of all square numbers under 50 and the set of all triangular numbers that are less than 50 disjoint?
Alina [70]

Answer:

No, the two sets are not disjoint.

Step-by-step explanation:

Set of triangular numbers to 50: 1, 3, 6, 10, 15, 21, 28, 36, 45

Set of square numbers to 50: 1, 4, 9, 16, 25, 36, 49

They have 1 and 36 in common, so they are not disjoint, or in other words, they have some of the same numbers.

7 0
3 years ago
Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf
erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

(\overline{x}_1-\overline{x}_2)\pm t^*\times SE ,

where (\overline{x}_1-\overline{x}_2) = sample mean difference .

t^*= critical t value (two-tailed)

SE= Standard error.

Given : (\overline{x}_1-\overline{x}_2)=23

t^*=2.262

SE= 4.2

Now, the confidence interval for mean difference will be :-

23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)

Hence, the required confidence interval : (13.4996, 32.5004)

8 0
3 years ago
1.A pizza place offers 6 different cheeses and 12 different toppings. In how many ways can a pizza be made with 1 cheese and 3 t
NNADVOKAT [17]
1.) You have 12 toppings. You choose one topping--that leaves you with 11 toppings. You choose another--that leaves 10. 12×11×10 = 1,320.
Multiply 1,320 topping choices by 6 cheeses to get 7,920 total combinations.

2.) (Though I'm less sure of these)
CDs: 6×5×4×3×2 = 720
Cassettes: 5×4 = 20
DVDs: 8×7×6×5 = 1680
4 0
3 years ago
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