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3 years ago

Y=-3x+4. What is the y intercept?

Mathematics

2 answers:

frutty [35]3 years ago

4 0

Answer:

Step-by-step explanation:

The equation is in the form

y= mx+b

where m is the slope and b is the y intercept

y = -3x +4

-3 is the slope and 4 is the y intercept

Wittaler [7]3 years ago

3 0

Answer:

y intercept is 4

Step-by-step explanation:

When you are finding the Y intercept, you need to pretend that x=0. Cover up the x and you would find the y-intercept which is 4

if it is wrong, let me know and I will fix it

hope this helps!

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136 is 85% of what number?

Arte-miy333 [17]

X * 0.85 = 136
x = 136/0.85
x = 160

hope this helps :)

3 0

3 years ago

Ill give brainliest

andreev551 [17]

First, make sure that all the variables are in one side. The first equation is gonna be x-y=3

Second, we are going to eliminate the y because it is much easier, but you can also eliminate the x

We have to add both equation because the y in the first equation is negative and in the second equation it’s positive.

We are left with 3x=9

Therefore, x=3

Last, substitute x= 3 in one of the equations

Y=6

P.O.I is (3,6)

8 0

3 years ago

The ratio between the radius of the base and the height of the cylinder is 2:3.if its volume is 1617cm^3,the total surface area

zalisa [80]

The answer is 769.3 cm²

The volume of the cylinder is : V = π r² h
<span>The ratio between the radius of the base and the height of the cylinder is 2:3:
r/h = 2/3
h = 3/2r

V = 1617 cm
</span>π = 3.14

1617 = πr² * 3/2 r
1617 = πr³ * 3/2
1617 * 2/3 = πr³
1078 = πr³
r³ = 1078/π = 1078/3.14 = 343
r = ∛343 = 7 cm

h = 3/2r = 3/2 * 7 = 10.5 cm

The surface area of the cylinder is:
SA = 2πr² + 2πrh
= 2 * 3.14 * 7² + 2 * 3.14 * 7 * 10.5
= 307.72 + 461.58
= 769.3 cm²

5 0

4 years ago

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$