(centimeter/minute): 17
(miles per hour): 0.00633799
325 meters if using full height of 324 meters for tower
277 meters if using observation platform height of 276 meters.
When the depression is 37 degrees, you can create a right triangle with the angles 90, 37, and 53 degrees. The distance from a point directly underneath the observer will be:
h/tan(37)
where
h = height of the observer.
And when the depression is 72 degrees, the distance will be:
h/tan(72)
So the distance between the two points will be the absolute value of:
h/tan(72) - h/tan(37)
=(tan(37)h)/tan(37)tan(72) - tan(72)h/(tan(37)tan(72))
=(tan(37)h - tan(72)h) /(tan(37)tan(72))
=h(0.75355405 - 3.077683537)/(0.75355405 * 3.077683537)
=h(0.75355405 - 3.077683537)/(0.75355405 * 3.077683537)
=h(-2.324129487/2.319200894)
=h*-1.002125125
And since we're looking for absolute value
=h*1.002125125
As for the value of "h" to use, that's unspecified in the problem. If you take h
to be the height of the Eiffel Tower, then it's 324 meters. If you take h to be
the highest observation platform on the Eiffel Tower, then it's 276 meters. In
any case, simply multiply h by the value calculated above:
=h*1.002125125
=324*1.002125125
= 324.6885406 m
=h*1.002125125
=276*1.002125125
=276.5865346
We want to find miles per hour.
Speed is distance over time.
So take 10 miles (distance) / 3 hours (time)
This is the same as 10/3.
10/3 = 3 and 1/3
Therefore, the girl is going 3 and 1/3 miles per hour.
Answer:
a) ∠EAB = 180° - 90° - 30° = 60°
∠EBA = 180° - 90° - 60° = 30°
a) ∠EBA = 30°
b) ∠DCA = 180° - 90° - 30° = 60°
∠EBA ≅ ∠DAC, ∠EAB ≅ ∠DCA, ∠AEB ≅ ∠CDA
ΔEBA ≅ ΔDAC because of the AAA postulate
c) EB ≅ DA, EA ≅ DC, AB ≅ CA
d) AB = CA given
sin ∠EAB = EB/AB (sin 60°) EB = (0.8660)AB
cos ∠EAB = EA/AB (cos 60°) EA = (0.5)AB
cos ∠DAC = AD/CA (cos 30°) AD = (0.8660)CA
sin ∠DAC = CD/CA (sin 30°) CD = (0.5)CA
ED = EA + AD
ED = (0.5)AB + (0.8660)CA
since AB = CA, ED = 1.366CA
since EB = (0.8660)AB and AB = CA, then EB = 0.866CA
since CD = 0.5CA,
EB + CD = 0.866CA + 0.5CA = 1.366CA
EB + CD = 1.366CA
1.366CA = 1.366CA
Proof: ED = EB + CD
Answer: The number is 26.
Step-by-step explanation:
We know that:
The nth term of a sequence is 3n²-1
The nth term of a different sequence is 30–n²
We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.
we get:
3n²- 1 = 30–m²
Notice that as n increases, the terms of the first sequence also increase.
And as n increases, the terms of the second sequence decrease.
One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.
if m = 1, then:
3n²- 1 = 30–1²
3n²- 1 = 29
3n² = 30
n² = 30/3 = 10
n² = 10
There is no integer n such that n² = 10
now let's try with m = 2, then:
3n²- 1 = 30–2² = 30 - 4
3n²- 1 = 26
3n² = 26 + 1 = 27
n² = 27/3 = 9
n² = 9
n = √9 = 3
So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.
the number is:
3*(3)² - 1 = 26
30 - 2² = 26
The number that belongs to both sequences is 26.
