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Elis [28]
3 years ago
13

Given AD|GJ. Refer to the figure and provide an appropriate name for

Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Check the picture below.

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Among the eighth-graders in Michael's school, 70% have siblings. The eighth-grade class is 5/6 the size of the seventh-grade cla
nikklg [1K]

Answer:

d. 192

Step-by-step explanation:

OK so if 70% of students in 8th grade have siblings and 112 8th graders have siblings, then:




0.7(total 8th graders) = 112


total 8th graders = 112/0.7


total 8th graders = 160




And since the number of 8th graders is 5/6 the size of the 7th grade class:


5/6(7th grade class) = 160


5(7th grade class) = 960


7th grade class = 192.




The correct answer is D) 192.


hope this helps can i be brainliest please

4 0
4 years ago
Which expression shows the sum of the polynomials with like terms grouped together? (8x+3z-8z^2)+(4y-5z)
nikitadnepr [17]
<span>8x+4y+(-8z^2)+[3z+(-5z)] the answer is D</span>
7 0
3 years ago
Read 2 more answers
What is the equation of a line that has an undefined slope and an X-intercept at negative 2? (Hint: x=2)
mrs_skeptik [129]
X=-2; undefined slope means that the line is vertical, and the question states that the x-intercept was negative 2.
3 0
3 years ago
Harold has 4 classes each School morning each class is 1 hour long and there are 10 minutes between classes the first class star
Katena32 [7]
Start at 8 a.m

First class and the break
8.00
1.00
-------- +
9.00
0.10
-------- +
9.10

Second class and the break
start at 9.10
9.10
1.00
------- +
10.10
0.10
-------- +
10.20

Third class and the break
start at 10.20
10.20
1.00
--------- +
11.20
0.10
-------- +
11.30

Fourth class (no break)
start at 11.30
11.30
1.00
-------- +
12.30

Fourth class end at 12.30
6 0
3 years ago
A statue is mounted on top of a 25 foot hill. From the base of the hill to where you are standing is 53 feet and the statue subt
bixtya [17]

Answer:15.848 ft

Step-by-step explanation:

Given Height of hill is 25 foot

and distance between Hill foot and feet is 53 feet

angle subtended by 12.4^{\circ}[/tex]

From diagram

tan\theta =\frac{25}{53}

tan(\theta +12.4)=\frac{h+25}{53}

and we know tan(A+B)=\frac{tanA+tanB}{1-tanAtanB}

using above formula

tan(\theta +12.4)=\frac{tan\theta +tan(12.4)}{1-tan(\theta )tan(12.4)}

\frac{h+25}{53}=\frac{\frac{25}{53}+0.219}{1-0.219\times \frac{25}{53}}

0.896h+22.407=25+11.607

h=15.848 ft

4 0
3 years ago
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