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Solnce55 [7]
3 years ago
9

Someone help me with question 2???

Mathematics
1 answer:
postnew [5]3 years ago
5 0
Surface area is the area of all the surfaces we can touch
2a)
1/2*5*3+1/2*4*3+6*4+6*5 which is
67.5

b) 2*(1/2*10*6)+12*6+12*10 which is
252
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Convert 510° from degrees to radians
vitfil [10]

Answer:

\frac{17\pi }{6}

Step-by-step explanation:

To convert from degrees to radians

radian = degree measure \frac{\pi }{180}

           = 510 × \frac{\pi }{180}

           = \frac{51\pi }{18}

           = \frac{17\pi }{6} radians

6 0
3 years ago
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yawa3891 [41]

Answer:

. ........

Step-by-step explanation:

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4 0
3 years ago
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HELP FAST‼️‼️
8_murik_8 [283]

Normal income: 25 $

Last week's income: 25 + 20: 45 $

% = Last week's/normal = 45/25 ×100 =180 %

7 0
2 years ago
Find the length of a side of an equilateral triangle given its altitude is six inches long.
vampirchik [111]
An equilateral triangle has three 60 degree angles.
The altitude divides it into two 30 60 90 triangles.
The altitude is the "middle side" of such a triangle.
When that is the case, the middle side divided by the square root of 3 = the short side and multiplied by (2/sq root (3)) equals the hypotenuse.
The hypotenuse is the side of the equilateral triangle. 
So, 6 * 2 / (sq root of 3) = <span> <span> <span> 6.9282032303 </span> </span> </span>

Source:
http://www.1728.org/trig2.htm


8 0
3 years ago
Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.
Mice21 [21]

Answer:

<em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

Step-by-step explanation:

Making factors of 8y^{6}+ 144y^{5}+ 640y^{4}

Taking 8y^{4} common:

\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)

Using <em>factorization</em> method:

\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times  4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)

Now, Making factors of 2y^{4} + 40y^{3} + 200y^{2}

Taking 2y^{2} common:

\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)

Using <em>factorization</em> method:

\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10)        ............ (2)

The underlined parts show the Highest Common Factor(HCF).

i.e. <em>HCF</em> is 2y^{2} (y+ 10).

We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

HCF \times LCM = p \times q

Using equations <em>(1)</em> and <em>(2)</em>: \Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times  4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)

Hence, <em>LCM</em> = 8y^{4}(y+ 10)^{2}(y + 8)

5 0
3 years ago
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