The firs term
A(1)=-6+(1-1)(6)
A(1)=-6+(0)(6)
A(1)=-6
The fourh term
A(n)=-6+(n-1)(6)
A(4)=-6+(4-1)(6)
A(4)=-6+(3)(6)
A(4)=-6+18
A(4)=12
The tenth term
A(10)=-6+(10-1)(6)
A(10)=-6+(9)(6)
A(10)=-6+54
A(10)=48
Answer:
D. -6,12,48
Answer:
Hey there!
That would be 7/8
Let me know if this helps :)
Answer:
Step-by-step explanation:
Because vertical angles are always equal, we want to solve 
.
We can add 10 to both sides to get 
.
We can subtract 
from both sides to get 
.
Lastly, we divide both sides by 20 to get 
.
So, 
and we're done!
The check is left as an exercise to the reader.
The total area of the given figure will be 66 square cm.
<h3>What is an area? </h3>
The space occupied by any two-dimensional figure in a plane is called the area. Here we have three shapes a triangle, a rectangle and a parallelogram.
Total area = Area of triangle + Area of rectangle + Area of parallelogram
Total area = [(1/2) x 4 x7] + [4 x 5] + [ 4 x 8 ]
Total area = 14+20+32
Total area = 66 square cm
Hence the total area of the given figure will be 66 square cm.
To know more about the area follow
brainly.com/question/24375372
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By Pythagoras AB^2 = 12^2 - 6^2 = 108
AB = sqrt 108 = 10.39 to nearest hundredth
The perpendicular from M to DC will be parallel and equal to AB so it = 10.39.
Also AB^2 = CB * DB
108 = 6 * DB
DB = 108/6 = 18
so DC = 18-6 = 12
MD^2 = (1/2*12)^2 + 108 = 144
so MD = 12
