Select the counterexample to this conjecture:
1 answer:
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The quadrants are as follows:
The 1st quadrant has the points which have both x and y positive and the 3rd quadrant has the points which have both x and y negative. If the ordered pair and the same x and y value, if ons is positive, the other also is, and the same for negative.
So, at first we see that there are point where the x and y are the same and that are in the 1st or 3rd quadrant.
However, there is one special case:
When x and y are 0, that is, the ordered pair is (0, 0).
Since this point is the origin, it doesn't lie on any of the quadrants.
Thus, this affirmative is sometimes true. Every point but (0, 0) that have same x and y values are in the 1st or 3rd quadrant except for (0, 0).
