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MrRa [10]
2 years ago
6

Let the function f(x) have the form f(x) = Acos(x - C). To produce a graph that

Mathematics
1 answer:
Ugo [173]2 years ago
7 0

Answer:

C=2

Step-by-step explanation:

Because I got it correct in AP3X

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The first graph is the answer. 
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(x+1) is a factor of the equation.
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Xavier is a salesperson who is paid a fixed amount of $455 per week. He also earns a commission of 3% on the sales he makes. If
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Evaluate NM if possible.
Sedaia [141]

The MN matrix is \left[\begin{array}{ccc}-2 & 1 & 0 \\17 & 2 & -3\\11 & 12 & -5\end{array}\right]\\.

What is matrix?

A matrix is a rectangular array or table with rows and columns of numbers, symbols, or expressions that is used to represent a mathematical object or an attribute of one. is a matrix having two rows and three columns, for instance.

Given M=\left[\begin{array}{cc} 1 & 0 \\ -4 & 3 \\ 2 & 5 \end{array}\right]

N=\left[\begin{array}{ccc}-2 & 1 & 0 \\3 & 2 & -1\end{array}\right]

M is a matrix with 3 * 2 dimension and N is a matrix with 2 * 3 dimension.

So finding MN is possible and the dimension will be 3 * 3.

Now,

MN=\left[\begin{array}{cc}1 & 0 \\-4 & 3 \\2 & 5\end{array}\right] \times \left[\begin{array}{ccc}-2 & 1 & 0 \\3 & 2 & -1\end{array}\right]\\= \left[\begin{array}{ccc}1 \times (-2)+0 \times 3 & 1 \times 1+0 \times 2 & 1 \times 0+0 \times (-1) \\(-2) \times (-4)+3 \times 3 & (-4) \times 1+3 \times 2 & (-4) \times 0+3 \times (-1) \\2 \times (-2)+5 \times 3 & 2 \times 1+5 \times 2 & 2 \times 0+5 \times (-1) \\\end{array}\right]\\

=\left[\begin{array}{ccc}-2 & 1 & 0 \\17 & 2 & -3\\11 & 12 & -5\end{array}\right]\\

Therefore the MN matrix is \left[\begin{array}{ccc}-2 & 1 & 0 \\17 & 2 & -3\\11 & 12 & -5\end{array}\right]\\.

To learn more about matrix from the given link

brainly.com/question/94574

#SPJ1

4 0
1 year ago
Complete the recursive formula of the arithmetic sequence 12, 10, 8, 6,...12,10,8,6,...12, comma, 10, comma, 8, comma, 6, comma,
pogonyaev

Complete Question:

Complete the recursive formula of the arithmetic sequence 12, 10, 8, 6, ....

b_1 = [\ ]

b_n = b_{n - 1} + [\ ]

Answer:

b_1 = 12

b_n = b_{n-1} - 2

Step-by-step explanation:

Required

Complete:

b_1 = [\ ]

b_n = b_{n - 1} + [\ ]

From the question, the first term is 12.

So:

b_1 = 12

Solving further:

b_2 = 10 = 12 - 2 = b_1 - 2

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b_4 = 6 = 8 - 2 = b_3 - 2

Following the above sequence:

b_n can then be calculated as

b_n = b_{n-1} - 2

4 0
3 years ago
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