Ask question

Ask question

All categories

3 years ago

14

The proof that ΔACB ≅ ΔECD is shown. Given: AE and DB bisect each other at C. Prove: ΔACB ≅ ΔECD What is the missing statement i

n the proof? ∠BAC ≅ ∠DEC ∠ACD ≅ ∠ECB ∠ACB ≅ ∠ECD ∠BCA ≅ ∠DCA

2 answers:

GarryVolchara [31]3 years ago

9 0

Answer:

The missing statement is ∠ACB ≅ ∠ECD

Step-by-step explanation:

Given two lines segment AC and BD bisect each other at C.

We have to prove that ΔACB ≅ ΔECD

In triangle ACB and ECD

AC=CE (Given)

BC=CD (Given)

Now to prove above two triangles congruent we need one more side or angle

so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles

hence, the missing statement is ∠ACB ≅ ∠ECD

ValentinkaMS [17]3 years ago

5 0

Answer with explanation:

Given: It is given that , in ΔACB and ΔE CD , A E and DB bisect each other at C.

To Prove: ΔA CB ≅ ΔE CD

Proof: In ΔA CB ,and ΔE CD

A E and DB bisect each other at C.

AC=CE -------[Given]

BC=CD-----[Given]

∠A CB = ∠E CD →→[Vertically opposite angles]

→∠A CB ≅ ∠E CD ⇒⇒[S A S]

Option C: →→∠A CB ≅ ∠E CD -------[missing statement in the proof]

You might be interested in

Inmultirea fractiilor

alexandr1967 [171]

Answer:

First, draw a rectangle and draw 3 lines going vertically. Then, draw the diagonal lines (shown in step 3) write the 4 digit number you are multiplying with the 1 digit number on top of the table (step 2) and multiply, when you are done multiplying, add the numbers vertically. Finally, you have your answer

Step-by-step explanation:

3 0

2 years ago

F(x) = -x^2 + 5x – 2<br> Find f(-4)

disa [49]

Answer:

2

Step-by-step explanation:

if f(4), than -4^2=-16

5(4)=20

-16+20-2=2

8 0

2 years ago

4x-3=5x-21 what does x=

torisob [31]

U subtract 4x by 5x and then you add 3 by -21 and the answer is x=18

3 0

3 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

I dont get this at all answer fast plz

Scrat [10]

Answer:

3960 Degrees

Step-by-step explanation:

There is a formula for this!

In this n=24 since there are 24 sides.

The formula is 180(n-2).

Hope this helped and please mark me as Brainliest if possible.

4 0

2 years ago