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noname [10]
2 years ago
9

PLEASE HELPPPP!!!!!!!!!!

Mathematics
1 answer:
AfilCa [17]2 years ago
6 0

Answer:

y = 2x/3 +6

Step-by-step explanation:

using the formula y=mx+b .........where m is the slope, b is the is the point, where the line intersects the y axis

y = 2/3 x + 6

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The graph below shows a company's profit f(x), in dollars, depending on the price of pens x, in dollars, sold by the company:
Volgvan

The answers to the various part as well as its reasons are given below

<h3 /><h3>Part A:</h3>
  • The x-intercepts shows a zero profit.
  • The maximum value of the graph tells  or depict the maximum profit.
  • The function is one that goes up or increases upward until it reach the vertex and then it falls or decreases after it.
  • This implies that the profit goes up as it reaches the peak at the vertex and it goes down after the vertex up until it gets to zero.
  • The  profits are negative as seen on the left of the first zero and on the right of the second zero.

<h3>Part B:</h3>

An approximate average rate of change of the graph from x = 3 to x = 5, shows the reduction in profit from  3 to 5.

<h3>Part C:</h3>

Based on the above,  the domain is one that is held back or constrained by x = 0 .

We are compelled at x = 6 due to the fact that we have to maneuver a negative profit.

Learn more about quadratic function from

brainly.com/question/25841119

#SPJ1

4 0
2 years ago
Estimate the sum 258+565
Thepotemich [5.8K]
So do 260+570 which is 830

The real sum is 823
7 0
3 years ago
3x + 7 = 9x + 3<br> No solution one solution or infinite
AlexFokin [52]

Answer:

One solution.  

Step-by-step explanation:

X=2/3 or x=2.6666

4 0
3 years ago
Read 2 more answers
Physics aka Physics
Triss [41]

Answer:

yeah physics is hard young one

4 0
2 years ago
Read 2 more answers
I do not know how to solve this problem or know what to do with the exponents
horsena [70]
K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also
(ab)^c=(a^c)(b^c)
and
x^{-m}= \frac{1}{x^m}
and
x^ \frac{m}{n}= \sqrt[n]{x^m}
and
( \frac{x}{y} )^m= \frac{x^m}{y^m}
and
(x^m)^n=x^{mn}
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)


so
( \frac{-7x^ \frac{3}{2} }{5y^4} )^{-2}=
( \frac{-7}{5} )^{-2}( \frac{x^ \frac{3}{2} }{y^4} )^{-2}=
( \frac{(-7)^{-2}}{5^{-2}} )( \frac{(x^ \frac{3}{2})^{-2} }{(y^4)^{-2}} )=
( \frac{ \frac{1}{(-7)^2} }{ \frac{1}{5^2} } )( \frac{x^ \frac{-6}{2} }{y^{-8}} )=
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{(x^{-3}) }{\frac{1}{y^8}} )
( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{\frac{1}{x^3} }{\frac{1}{y^8}} )=
(\frac{25}{49} )( \frac{y^8}{x^3}=
\frac{25y^8}{49x^3}
4 0
3 years ago
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