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navik [9.2K]
2 years ago
13

Cans of soda at a local store a six-pack of soda costs $2.59 and indivdual cans cost $0.80. What is the maximum of cans of soda

that can be purchased for $15​
Mathematics
1 answer:
iren [92.7K]2 years ago
8 0

Answer:  30 cans (buy them by the six-pack; so you'd buy 5 six-packs)

==============================================================

Explanation:

Let's say you buy six-packs only. Divide the amount of money you have over the cost per six-pack.

15/(2.59) = 5.7915 which rounds down to 5.

If you buy six-packs only, then you can buy a max of 5 of them. That gets you 5*6 = 30 cans of soda.

-------------

Now let's say you buy individual cans only. We'll use the same idea mentioned earlier but this time divide over 0.80

15/(0.80) = 18.75 which rounds down to 18

We round down because we can't buy that 19th can of soda (note how 19*0.80 = 15.2 which is larger than 15).

So if you buy individual cans only, then you can get a max of 18 cans.

We see that it's better to go with the six-pack option (in the first section) since we can get 30 cans compared to 18 cans.

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Answer:

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Step-by-step explanation:

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<h3>Exercise 4</h3>

<u>Pentagon has sum of angles:</u>

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<u>Sum the given angles and find x:</u>

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<h3>Exercise 5</h3>

<u>Hexagon has sum of angles:</u>

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<u>Sum the given angles and find x:</u>

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2 years ago
Can 33.0 convert into a fraction for example 330/100, would it be able to convert?
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3 years ago
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guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

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Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

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z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

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Romashka-Z-Leto [24]

Answer:Hello! Here we have a cube, with a mass of 10g and a side length of 2.5cm.

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The volume of a cube, is equal to his cubic side length, where  L is the side length:

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So the volume of the cube is 15.625 cubic centimeters.

Now we want to calculate te density of the material, as you know:

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Step-by-step explanation:

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