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3 years ago

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A two-digit random number is chosen. What is the probability that the sum of its digits is 5?

2 answers:

MrMuchimi3 years ago

8 0

10≤n<100

So the number of two digit numbers is 99-10+1=90

The only combinations that sum to 5 are 14, 23, 32, 41, 50 so

P(sum=5)=5/90

P(sum=5)=1/18

Brrunno [24]3 years ago

6 0

There are 90 two digit numbers.
The numbers that have 5 as the sum of their digits are:
14,23,32,41,50
which are 5 numbers out of the possible 90

Therefore the probabilty is 5/90 or 1/18

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Solve by factorising<br><br><img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="abs

Paladinen [302]

Step-by-step explanation:

$\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :$

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

$\underline{ \underline{ \text{Let's \: solve}}} :$

$\tt{ {x}^{2} + 16x + 55 = 0}$

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ $\tt{ {x}^{2} + (11 + 5)x + 55 = 0}$

⤑ $\tt{ {x}^{2} + 11x + 5x + 55 = 0}$

⤑ $\tt{x(x + 11) + 5(x + 11) = 0}$

⤑ $\tt{(x + 5)(x + 11) = 0}$

Either :

$\tt{x + 5 = 0 \: \: \: \: \: \: \: \: \: \: \: \: \: Or : \: \: x + 11 = 0}$

$\sf{⟶ x = 0 - 5} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:⟶ x = 0 - 11$

$\tt{⟶x = - 5 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:⟶ x = - 11$

$\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer : \boxed{ \underline{ \bold{ \tt{x = - 5 \: , - 11}}}}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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koban [17]

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3 years ago

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Find three consecutive integers such that the sum of the largest and 5 times the smallest is -244. URGENT

Bad White [126]

Answer:

-39+5(-41)=244

Step-by-step explanation:

Consider 3 consecutive integers: (smallest) x, x+1 and x+2 (largest)

Five times the smallest means 5x

Sum of the largest and five times the smallest means x+2+5x

This sum is -244 means x+2+5x=-244

Solve this equation

x+2+5x=-244

6x+2=-244

6x=-244-2

6x=-246

x=-41

So, smallest number is -41, second is -40 and largest is -39

= -39+5(-41)=244

Hope this helps, have a nice day/night! :D

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algol13

Answer:

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Andreas93 [3]

The answer is 53
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