Answer:
0%
Explanation:
From the information given;
Assume that the dominant "B" allele encodes brown eyes ; and
the recessive "b" allele encodes blue eyes
If genotype BB × genotype bb, the percentage of chance that they would have children with blue eyes will be zero ...Let look at the cross
BB × bb
We have all the progeny as Bb, Bb, Bb, Bb ....i.e the genotypic information are all heterozygous brown eyes, this is because The allele B mask the recessive "b" allele which makes the allele B (brown eyes) to be dominant over allele b (blue eyes).
Brian : Information being sent throughout the body.
Spinal cord: Sends sensory messages.
PNS: connects to the central nervous system
Prokaryotic Microorganism's
Answer:
C. There is a 75% probability that an offspring will have brown eyes and a 25% probability that an offspring will have blue eyes.
Explanation:
Note that the brown eyes is the dominant trait, denoted by B, while blue eyes is the recessive trait, denoted by b. In all cases of the Punnett square, if there is a dominant and recessive trait, the dominant trait will always come out on top.
The given Punnett square:
![\left[\begin{array}{ccc}&B&b\\B&BB&Bb\\b&Bb&bb\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%26B%26b%5C%5CB%26BB%26Bb%5C%5Cb%26Bb%26bb%5Cend%7Barray%7D%5Cright%5D)
Note that there are 3 options (BB, Bb, Bb) respectively, in which there is the dominant trait B (brown eyes). Only in one case is there only the recessive trait b (blue eyes), or a 1/4 chance of obtaining blue eyes. Therefore, there is a 3/4 chance of obtaining a brown eye:
C. There is a 75% probability that an offspring will have brown eyes and a 25% probability that an offspring will have blue eyes.
Answer:
Explanation:
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