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Ivenika [448]
2 years ago
7

Solve: y = -7(-13). GIVING BRAINLIST HURRY UP!!!

Mathematics
1 answer:
sesenic [268]2 years ago
5 0

Answer:

The answer is 91

Step-by-step explanation:

~Hoped this helped~

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Branliest and Extra Points will be given!!! No explanation needed just the answer plz.
Hitman42 [59]

Right triangle, Pythagorean Theorem:

c² = a² + b²

a=8, b=9

c² = 8² + 9²  = 64 + 81 = 145

c = √145 inches

That's the exact answer but they want us to ruin it with an approximation.

c ≈ 12.041594578792296 inches

Answer: 12

3 0
3 years ago
Solve for Unknown: x/10=43/46.
sergey [27]

Answer:

9

Step-by-step explanation:

x= 430/46

x=9.35 approximately 9( nearest whole number)

4 0
1 year ago
A spaceship is traveling at a steady rate. The table shows the distance the spaceship travels in a given period of time. Find th
nika2105 [10]

The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.

<h3>What is the distance the spaceship travels in 4 minutes?</h3>

The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;

Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.

Consequently, we can evaluate the distance travelled after 4 minutes as;

Distance = 200 × 4 = 800mi.

Ultimately, the distance travelled per minute by the spaceship is; 800mi.

Remarks:

600 miles

520 miles

800 miles

1,080 miles

Read more on ratios;

brainly.com/question/13513438

#SPJ1

4 0
1 year ago
A rectangle has a length that is 10 less than 3 times the width. If the rectangle has an area of 8 square feet, what is the widt
JulijaS [17]

Solve this problem by forming an equation

3x - 10 = 8

3x = 18

The width of the rectangle is 6 square feet.

3 0
3 years ago
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


3 0
3 years ago
Read 2 more answers
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