Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
The answer to this is .15%
Answer:
Step-by-step explanation:
Instead of dividing both sides by 5, it is multiplied
5x + 3 = 6 {Subtract 3 from both sides}
5x + 3 - 3 = 6-3
5x = 3 {Divide both sides by 5}
5x/5 = 3/5
x = 3/5
Answer:
Slope = 
4x + 3y = 23
Step-by-step explanation:
slope = 
The equation:
m is the slope
y - 5 = -4/3 (x - 2) Multiply both sides by 3
3y -15 = -4 (x - 2)
3y - 15 = -4x + 8
3y + 4x = 8 + 15
3y + 4x = 23
4x + 3y = 23
Answer:
probability that contractor 1,2 and 3 win is 33%,50% and 17% respectively
Step-by-step explanation:
assuming that there are no other contractors then:
probability that 1 , 2 or 3 win = 1
denoting as X= probability that contractor 3 wins , then assuming that only one wins , we have
probability that 1 , 2 or 3 win = 1
probability that contractor 1 wins + probability that contractor 2 wins + probability that contractor 3 wins = 1
2*P(X) + 3*P(X) + P(X) = 1
6*P(X) = 1
P(X) =1/6
then
-probability that contractor 1 wins = 2/6 (33%)
-probability that contractor 3 wins = 3/6 (50%)
-probability that contractor 3 wins = 1/6 (17%)
