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NeTakaya
3 years ago
8

X = 1, 2, 3 , 4 ,5

Mathematics
2 answers:
exis [7]3 years ago
5 0

Answer:

  • y = -3x + 18

Step-by-step explanation:

<u>We can see:</u>

  • x- values increase by 1 unit
  • y- values decrease by 3 units (slope is -3).

<u>This is a linear relationship. Use point-slope form to find the equation:</u>

  • y - 15 = -3(x - 1)
  • y = -3x + 3 + 15
  • y = -3x + 18
Vera_Pavlovna [14]3 years ago
3 0
X goes by 1s

And y goes by 3s
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Find the probability P(z &lt; 0.37) using the standard normal distribution.
dimaraw [331]

Answer:

0.6443

Step-by-step explanation:

Given the that:

P(Z < 0.37) ; using a standard normal distribution :

The probability can be obtained using several methods :

Using a standard normal distribution table ;

P(Z < 0.37) = obtain the value at the intersection where 0.3 is on the vertical axis and 0.07 on the horizontal axis of the Z distribution table

Hence,

P(Z < 0.37) = 0.6443

4 0
3 years ago
n △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP. Find the area of △ABC if the area of △BMP is
monitta

Answer: The area of ABC is 56 m².

Explanation:

It is given that in △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP.

Since point P divides the line AB in 1:3, therefore the area of triangle APC and BPC is also in ratio 1:3. To prove this draw a perpendicular h on AB from C.

\frac{\text{Area of } \triangle BCP}{\text{Area of } \triangle ABC} =\frac{\frac{1}{2}\times BP\times CH}{\frac{1}{2}\times AB\times CH} =\frac{BP}{AB}= \frac{3}{4}

Since the area of BPC is \frac{3}{4}th part of total area, therefore area of APC is  \frac{1}{4}th part of total area.

The point M is the midpoint of CP, therefore the area of BMP and BMC is equal by midpoint theorem.

\text{Area of } \triangle BMP=\text{Area of } \triangle BMC

21=\text{Area of } \triangle BMC

Area of BPC is,

\text{Area of } \triangle BPC=\text{Area of } \triangle BMP+\text{Area of } \triangle BMC

\text{Area of } \triangle BPC=21+21

\text{Area of } \triangle BPC=42

Area of APC is,

\text{Area of } \triangle APC=\frac{1}{3}\times \text{Area of } \triangle BPC

\text{Area of } \triangle APC=\frac{1}{3}\times 42

\text{Area of } \triangle APC=14

Area of ABC is,

\text{Area of } \triangle ABC=\text{Area of } \triangle APC+\text{Area of } \triangle BPC

\text{Area of } \triangle ABC=14+42=56

Therefore, the area of ABC is 56 m².

5 0
3 years ago
A window is twice as long as it is wide. The area of the window is 2x where x
Alchen [17]

Answer:

When we have a rectangle of length L and width W, the area is calculated as:

A = W*L

In this case, W = x, and the area is:

A = 2*x

Then we must have  L = 2.

We know that the area of the window and the frame (together) is:

a = 2*x^2 + 12*x + 16

The area of the frame alone, will be equal to the difference between the area of both objects (a) and the area of the window alone (A)

area of the frame = a - A

                             = (2*x^2 + 12*x + 16) - (2*x) = (2*x^2 + 10*x + 16)

This is the area of the frame

5 0
3 years ago
Whats 12% in a fraction and decimal
Yuki888 [10]
Answer : 0.12 ( decimal ) 12/100 ( fraction )
5 0
3 years ago
Read 2 more answers
What is the equation in point−slope form of the line passing through (2, 2) and (4, 8)?
irina [24]
It is definitely (y-2)=3(x-2)
8 0
3 years ago
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