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Leya [2.2K]
4 years ago
6

Can someone give me a simple definition for absolute value

Mathematics
2 answers:
kkurt [141]4 years ago
7 0
The distance a number is from zero
Vitek1552 [10]4 years ago
6 0
Absolute value is h<span>ow far a number is from zero.
</span>
For example |-4|=4 or |98| =98. 

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For <img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%204x%2B1" id="TexFormula1" title="f(x) = 4x+1" alt="f(x) = 4x+1" align="abs
Kamila [148]

\bf \begin{cases} f(x)=4x+1\\ g(x)=x^2-5\\[-0.5em] \hrulefill\\ (f\circ g)(4)=f(~~g(4)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ g(4)=(4)^2-5\implies g(4)=16-5\implies \boxed{g(4)=11} \\\\\\ f(~~g(4)~~)\implies f(11)\implies f(11)=4(11)+1\implies \blacktriangleright f(11)=45\blacktriangleleft

3 0
3 years ago
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#11! Plzzz help Algebra 2 Honors :))))
dmitriy555 [2]

A vertical asymptote simply means that the function is undefined at a certain point. We are given that it occurs at x=25. Notice that x is in the denominator and if the denominator equals 0, the entire function is undefined. <em>a</em> and <em>k</em> are simply constants, and so they can take on any value. This is one of infinite solutions to this question:

f(x) = \frac{\pi}{x-25} + e^6

Notice that when you plug in x=25, the denominator is 0 and the function is undefined making it a vertical asymptote.

Hope I could help!

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5C%5C%20jn%20j%20j%20j" id="TexFormula1" title="\\ jn j j j" alt="\\ jn j j j" align="absmidd
labwork [276]

Answer:

glhIblzikdjbgjdzgbobrgbzoerbgoernbs

Step-by-step explanation:

ur welcome ;)

6 0
3 years ago
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What’s the answer to this
JulsSmile [24]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
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Please solve each of the following by factoring!
Oxana [17]

Answer:

see explanation

Step-by-step explanation:

(a)

x² - 36 = 0 ← is a difference of squares and factors as

(x - 6)(x + 6) = 0

equate each factor to zero and solve for x

x + 6 = 0 ⇒ x = - 6

x - 6 = 0 ⇒ x = 6

(b)

x² - 5x + 4 = 0

consider the product of the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)

the factors are - 1 and - 4 , since

- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then

(x - 1)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 4 = 0 ⇒ x = 4

(c)

x² - 2x = 3 ( subtract 3 from both sides )

x² - 2x - 3 = 0 ← in standard form

consider the product of the factors of the constant term (- 3) which sum to give the coefficient of the x- term (- 2)

the factors are + 1 and - 3 , since

1 × - 3 = - 3 and 1 - 3 = - 2 , then

(x + 1)(x - 3) = 0 ← in factored form

equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

x - 3 = 0 ⇒ x = 3

(d)

6x² - 11x - 10 = 0

consider the product of the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 6 × - 10 = - 60 and sum = - 11

the factors are + 4 and - 15

use these factors to split the x- term

6x² + 4x - 15x - 10 = 0 ( factor the first/second and third/fourth terms )

2x(3x + 2) - 5(3x + 2) = 0 ← factor out (3x + 2) from each term

(3x + 2)(2x - 5) = 0

equate each factor to zero and solve for x

3x + 2 = 0 ⇒ 3x = - 2 ⇒ x = - \frac{2}{3}

2x - 5 = 0 ⇒ 2x = 5 ⇒ x = \frac{5}{2}

6 0
2 years ago
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