Given Information:
Mass = m = 20000 kg
Height of ramp = h = 0.840 m
Length of ramp = L = 20 m
Required Information:
Uphill Force = F = ?
Answer:
F = 8232 N
Explanation:
The force can be found using the equation
F = mgsinθ
Where m is the mass of block, g is the acceleration due to gravity
Since the ramp can be modeled as an inclined plane so it can formed into a triangle, recall that in right angle triangle sinθ is equal to opposite over hypotenuse. The opposite is the height and hypotenuse is the ramp surface.
sinθ = h/L = 0.840/20 = 0.042
F = 20000*9.8*0.042
F = 8232 N
Therefore, an uphill force of 8232 N would be needed.
According to another source this is what I got
<span>0.735 J ( Ep-potential energy, m-mass,g-gravitational acceleration = 9.81m/s², h-height; Ep = m * g * h; Ep = 0.0300 kg * 9.81 m/s² * 2.5 m )
</span>Hope it helps
For the velocity graph: start at 0s and 4m/s and draw a straight line to 2s and 2 m/s. Then draw a straight horizontal line to 4s and 2m/s
For the acceleration graph: start with a horizontal line from 0s and 2m/s/s to 2s and 2m/s/s. The draw another line from 2 s and 0m/s/s to 4 s and 0m/s/s
Answer:
t = 2.55 s
Explanation:
Given that,
Height from which the baseball is thrown, h = 155 m
Initial velocity of the baseball, u = -25 m/s
We need to find the time taken by it to reach the ground. Let the time is t. Using equation of kinematics to find it as follows:
So, it will take 2.55 seconds to reach the ground.
Answer:
Explanation:
mass of refrigerator, m = 110 kg
coefficient of static friction, μs = 0.85
coefficient of kinetic friction, μk = 0.59
(a) the minimum force required to just start the motion in refrigerator
F = μs x mg
F = 0.85 x 110 x 9.8
F = 916.3 N
(b) The force required to move the refrigerator with constant speed
F' = μk x mg
F' = 0.59 x 110 x 9.8
F' = 636.02 N
(c) Let a be the acceleration.
Net force = Applied force - friction force
F net = 950 - 636.02
F net = 313.98 N
a = F net / mass
a = 313.98 / 110
a = 2.85 m/s²