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enyata [817]
3 years ago
15

Why can we say that the ratio of net force to mass is constant forany dropped object on Earth?

Physics
1 answer:
vaieri [72.5K]3 years ago
4 0

Answer:

All objects free fall at the same rate regardless of their mass. Because the 9.8 N/kg gravitational field at Earth's surface causes a 9.8 m/s/s acceleration of any object placed there, we often call this ratio the acceleration of gravity.

Explanation:

Newton's Second Law, if I remember right.

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A car of mass 775 kg traveling at a velocity of 30 m/s in the positive x-direction crashes into the rear of a truck of mass 1,47
Thepotemich [5.8K]

Answer:

velocity of the car is 7.3516 m/s

Explanation:

M1v1a + m2v1b = m1v2a + m2v2b

775*30 + 1475*0 = 775*v2a+1475*11.9

Let v2a be x

23250 + 0 = 775x + 17552.5

775x = 23250-17552.5

775x = 5697.5

X = 7.3516 m/s

4 0
3 years ago
The u.s army’s parachuting team, the Golden Knights, are on a routine
quester [9]

The average force is -2600 N

Explanation:

First of all, we need to calculate the acceleration of the man during the collision, which is given by the suvat equation:

v^2-u^2=2as

where:

v = 0 is his final velocity (he comes to a stop)

u = 4.0 m/s is the initial velocity

a is the acceleration

s = 0.20 m is the distance covered

Solving for a,

a=\frac{v^2-u^2}{2s}=\frac{0-4.0^2}{2(0.20)}=-40 m/s^2

The negative sign indicates that it is a deceleration.

Now we can find the average force on the man by using Newton's second law of motion:

F=ma

where

m = 65 kg is the mass

a=-40 m/s^2

And substituting,

F=(65)(-40)=-2600 N

where the negative sign indicates the force is in the direction opposite to the motion.

Learn more about force and Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

7 0
4 years ago
A hot-air balloon is rising straight up with a speed of 1.30 m/s. A ballast bag is released from rest relative to the balloon wh
DiKsa [7]

Answer:

The time before the ballast hits the ground is 1.186918s

Explanation:

We assume that the upward direction is positive.

The bag released from the ballon is at rest. The velocity of the bag equals the velocity of the balloon.

The balloon has a velocity (V0y) = 3m/s

When the bag is released, it has a height of 5.36m

To touch the ground it makes a displacement of y = - 5.36m

The motion of the bag can be described as followed:

y = V0t + 1/2 * at²

t² + (2V0/a)*t - (2y/a) = 0

We can solve this equation for t:

t= ((-2V0/a) ± √((2V0/a)² + 4*(2y/a))) /2

t = -(V0/a) ± √((V0/a)² + (2y/a))

In this equation we can plug the given values ( V0 = 1.3 m/s ; y = 5.36m ; g =-9.8 m/s²)

t = (1.3/-9.8)±√((1.3/-9.8)²+(2*(-5.36)/-9.8))

t = 0.132653 ± 1.054266

t= 1.186918

The time before the ballast hits the ground is 1.186918s

6 0
3 years ago
A 62.3 N force pulls an object at an angle of 9 = 22.0° to its direction of horizontal motion. It moves a
Debora [2.8K]

W = F cos α . d

W = 62.3 cos 22 . 12.1

W = 698.94 J

8 0
2 years ago
While playing her guitar , karen plucks one string with increasing levels of force. What effect does this have on the sound prod
Lena [83]

Answer:

The amplitude of vibration of string will increase due to which loudness of sound will increase

Explanation:

As we know that the guitar is based on the principle of Resonance. When string of the guitar vibrates at a given frequency then the sound produced in the hollow part of the guitar will also be at same frequency.

This is known as resonance condition, so guitar will produce same frequency sound as that of frequency of string.

Now if the string is plucked with increasing level of force then it will increase the amplitude of vibrations of the string due to which the sound produced in the guitar will also be of same level.

So here we can say that amplitude and intensity of sound related as

I = kA^2

so on increasing amplitude the intensity will increase and hence it will produce loud sound

8 0
3 years ago
Read 2 more answers
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