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cestrela7 [59]
2 years ago
11

Marcus asked 10 people at a juggling festival what age they were when they started to juggle

Mathematics
1 answer:
Scrat [10]2 years ago
6 0

Question

Marcus asked 10 people at a juggling festival what age they were when they started to juggle. Which interval contains the median age?

Answer:

See Explanation

Step-by-step explanation:

Given

n = 10

Required

The median interval

The question is incomplete, as the required data is not given.

To solve this question, I will use the following assumed dataset.

Age:17\ 17\ 18\ 20\ 21\ 22\ 22\ 24\ 28\ 28

First, calculate the median position.

Median = \frac{n+1}{2}\ th

Median = \frac{10+1}{2}\ th

Median = 5.5\ th

This implies that the median is the mean of the 5th and 6th data

So, we have the interval to be.

Median = [5th, 6th]

Median=[21,22]

<em>Generally, the median of 10 data set is located at interval 5 to 6</em>

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seropon [69]
This question is not understandable. Can you rewrite it again please?
5 0
3 years ago
PLZ HELP!!! Use limits to evaluate the integral.
Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

r_i=\dfrac{2i}n

where 1\le i\le n. Each interval has length \Delta x_i=\frac{2-0}n=\frac2n.

At these sampling points, the function takes on values of

f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}

We approximate the integral with the Riemann sum:

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3

Recall that

\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4

so that the sum reduces to

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}

Just to check:

\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28

4 0
2 years ago
A valid license plate in Xanadu consists of two capital letters followed by three digits. How many valid license plates are poss
tatiyna

The  valid license plates are possible = 676,000 possibilities

<h3>What is permutation and combination?</h3>

In mathematics, there are two alternative methods for dividing up a collection of components into subsets: combination and permutation. The subset's components can be arranged in any sequence when used together. The subset's components are given in a permutation in a certain order.

<h3>According to the given information:</h3>

There is no prohibition on using the same letters or numbers more than once, therefore all 26 letters of the alphabet and all 10 numerals are permissible choices.

There are 26 options if the initial answer is A:

AA, AB, AC,AD,AE ...................................... AW, AX, AY, AZ.

There are 26 options if the initial answer is B:

BA, BB, BC, BD, BE .........................................BW, BX,BY,BZ

So,

The first letter can be one of 26 options, and the second letter can be one of 26 options. There are a variety of 2 letter combinations, including:

26 x 26 = 676

For the three digits, the same holds true.

The first, second, and third options each have ten options available:

10  × 10 × 10 = 1000

Thus, there are several options for a license plate with two letters and three digits:

26 x 26 x 10  × 10 × 10 =  676,000 possibilities.

The  valid license plates are possible = 676,000 possibilities.

To know more about permutation and combination visit:

brainly.com/question/13387529

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8 0
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What digit makes each number divisible by nine?<br><br> _7,302
Alborosie

Answer:

Not completely sure but hopefully these will help.

Step-by-step explanation:

I'm kind of confused what you're asking for. If you could clarify that would be great. If you're trying to make it divisible by 9, you can either do 3, 6 or 9. If you want the first two digits: 2,5,8. Please clarify so I can help

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