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AnnyKZ [126]
2 years ago
10

Really need help! anything would be appreciated

Mathematics
2 answers:
Citrus2011 [14]2 years ago
5 0
Here's anything for you :D





Jk, the answer is 6x + 16y + 8 :)
Arada [10]2 years ago
4 0
It's the second one...
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Please help i got a f on it and i am redoing it i will give 28 points for the right answer
Savatey [412]

Answer:

11/16

Step-by-step explanation:

12 divided by (2+2/3)^2 =1.6875

1.6875 in a decimal form is 11/16

5 0
2 years ago
Read 2 more answers
Freezer A measures 1 ft times 1 ft times 5 ft and sells for ​$300. Freezer B measures 1.5 ft times 1.5 ft times 4 ft and sells f
Sladkaya [172]

Answer:

Freezer A is better option as price per cubic foot is less for Freezer A

Step-by-step explanation:

Data provided in the question:

Measure of Freezer A = 1 ft × 1 ft × 5 ft

Measure of Freezer B = 1.5 ft × 1.5 ft × 4 ft

Price of Freezer  A = $300

Price of Freezer  B = $600

Now,

Volume of Freezer A = 1 ft × 1 ft × 5 ft

= 5 ft³

Volume of Freezer B = 1.5 ft × 1.5 ft × 4 ft

= 9 ft³

Now,

Price per cubic foot for Freezer A = $300 ÷ 5 ft³

= $60/ft³

Price per cubic foot for Freezer B = $600 ÷ 9 ft³

= $66.67/ft³

Hence,

Freezer A is better option as price per cubic foot is less for Freezer A

7 0
2 years ago
Can someone help me do part two please? It’s very important send a picture or something. I don’t even care if you tell me the st
Nataly_w [17]
<h3>Explanation:</h3>

1. "Create your own circle on a complex plane."

The equation of a circle in the complex plane can be written a number of ways. For center c (a complex number) and radius r (a positive real number), one formula is ...

  |z-c| = r

If we let c = 2+i and r = 5, the equation becomes ...

  |z -(2+i)| = 5

For z = x + yi and |z| = √(x² +y²), this equation is equivalent to the Cartesian coordinate equation ...

  (x -2)² +(y -1)² = 5²

__

2. "Choose two end points of a diameter to prove the diameter and radius of the circle."

We don't know what "prove the diameter and radius" means. We can show that the chosen end points z₁ and z₂ are 10 units apart, and their midpoint is the center of the circle c.

For the end points of a diameter, we choose ...

  • z₁ = 5 +5i
  • z₂ = -1 -3i

The distance between these is ...

  |z₂ -z₁| = |(-1-5) +(-3-5)i| = |-6 -8i|

  = √((-6)² +(-8)²) = √100

  |z₂ -z₁| = 10 . . . . . . the diameter of a circle of radius 5

The midpoint of these two point should be the center of the circle.

  (z₁ +z₂)/2 = ((5 -1) +(5 -3)i)/2 = (4 +2i)/2 = 2 +i

  (z₁ +z₂)/2 = c . . . . . the center of the circle is the midpoint of the diameter

__₁₂₃₄

3. "Show how to determine the center of the circle."

As with any circle, the center is the <em>midpoint of any diameter</em> (demonstrated in question 2). It is also the point of intersection of the perpendicular bisectors of any chords, and it is equidistant from any points on the circle.

Any of these relations can be used to find the circle center, depending on the information you start with.

As an example. we can choose another point we know to be on the circle:

  z₄ = 6-2i

Using this point and the z₁ and z₂ above, we can write three equations in the "unknown" circle center (a +bi):

  • |z₁ - (a+bi)| = r
  • |z₂ - (a+bi)| = r
  • |z₄ - (a+bi)| = r

Using the formula for the square of the magnitude of a complex number, this becomes ...

  (5-a)² +(5-b)² = r² = 25 -10a +a² +25 -10b +b²

  (-1-a)² +(-3-b)² = r² = 1 +2a +a² +9 +6b +b²

  (6-a)² +(-2-b)² = r² = 36 -12a +a² +4 +4b +b²

Subtracting the first two equations from the third gives two linear equations in a and b:

  11 -2a -21 +14b = 0

  35 -14a -5 -2b = 0

Rearranging these to standard form, we get

  a -7b = -5

  7a +b = 15

Solving these by your favorite method gives ...

  a +bi = 2 +i = c . . . . the center of the circle

__

4. "Choose two points, one on the circle and the other not on the circle. Show, mathematically, how to determine whether or not the point is on the circle."

The points we choose are ...

  • z₃ = 3 -2i
  • z₄ = 6 -2i

We can show whether or not these are on the circle by seeing if they satisfy the equation of the circle.

  |z -c| = 5

For z₃: |(3 -2i) -(2 +i)| = √((3-2)² +(-2-i)²) = √(1+9) = √10 ≠ 5 . . . NOT on circle

For z₄: |(6 -2i) -(2 +i)| = √((6 -2)² +(2 -i)²) = √(16 +9) = √25 = 5 . . . IS on circle

4 0
3 years ago
If y = 7x – 5, which of the following sets represents possible inputs and outputs of the function, represented as ordered pairs?
Setler79 [48]
The third set, (0, -5) (2,9) (-3,-26)
3 0
2 years ago
Read 2 more answers
What is the answer for this algebra question 4(2n-5)=3n+10
miss Akunina [59]
4(2n-5)=3n+10\\\\&#10;8n-20=3n+10\ \ \ |Subtract\ 3n\\\\&#10;5n-20=10\ \ \ Add\ 20\\\\&#10;5n=30\ \ \ |Divide\ by\ 5\\\\&#10;n=\frac{30}{5}=6\\\\Solution\ is\ n=6.
4 0
3 years ago
Read 2 more answers
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