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malfutka [58]
3 years ago
12

Somebody help me please

Mathematics
1 answer:
Sauron [17]3 years ago
3 0

Answer:

Here is the answer with the steps

Step-by-step explanation:

Hope you liked it!!

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Each year for 3 years, the time it takes you to run a mile decreases by 10 seconds. Find the total change time
hichkok12 [17]

Answer: 109.5

Step-by-step explanation: EACH year for three years would be 1095 if you  multiply 365 (each year) by 3 (the amount of years) and then divide that by 10. Im not entirely sure but I hope I helped

7 0
3 years ago
What is 4^0 in exponential form?
Nesterboy [21]
Anything to the power of 0 is just 1
6 0
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Miguel reads 3/4 chapters in 4/5 hours. What is the unit rate in chapters per hour?
kap26 [50]
If its multiplication sipmlest form is, 6/10
If its addition simplest form is, 7/9
If its any other just tell me! Hope i was right :p
8 0
3 years ago
10x+8=3(x-2) 10x+8=3x-6
d1i1m1o1n [39]

Answer:

x = -2

Step-by-step explanation:

10x+8=3x-6

subtract 10x-3x

7x+8= -6

subtract -6-8

7x=-14

divide 7 into -14

x = -2

Hope this helps!

4 0
3 years ago
Solve the following differential equations or initial value problems. In part (a), leave your answer in implicit form. For parts
shepuryov [24]

Answer:

(a) (y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) y = arctan(t(lnt - 1) + C)

(c) y = -1/ln|0.09(t + 1)²/t|

Step-by-step explanation:

(a) dy/dt = (t^2 + 7)/(y^4 - 4y^3)

Separate the variables

(y^4 - 4y^3)dy = (t^2 + 7)dt

Integrate both sides

(y^5)/5 + y^4 = (t^3)/3 + 7t + C

(b) dy/dt = (cos²y)lnt

Separate the variables

dy/cos²y = lnt dt

Integrate both sides

tany = t(lnt - 1) + C

y = arctan(t(lnt - 1) + C)

(c) (t² + t) dy/dt + y² = ty², y(1) = -1

(t² + t) dy/dt = ty² - y²

(t² + t) dy/dt = y²(t - 1)

(t² + t)/(t - 1)dy/dt = y²

Separating the variables

(t - 1)dt/(t² + t) = dy/y²

tdt/(t² + t) - dt/(t² + t) = dy/y²

dt/(t + 1) - dt/(t(t + 1)) = dy/y²

dt/(t + 1) - dt/t + dt/(t + 1) = dy/y²

Integrate both sides

ln(t + 1) - lnt + ln(t + 1) + lnC = -1/y

2ln(t + 1) - lnt + lnC = -1/y

ln|C(t + 1)²/t| = -1/y

y = -1/ln|C(t + 1)²/t|

Apply y(1) = -1

-1 = ln|C(1 + 1)²/1|

-1 = ln(4C)

4C = e^(-1)

C = (1/4)e^(-1) ≈ 0.09

y = -1/ln|0.09(t + 1)²/t|

8 0
3 years ago
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