Find the exact length of the third side. 39 36

Mathematics

1 answer:

Paul [167]3 years ago

7 0

The answer is 15 cm

39 cm, 15 cm, 36 cm

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A class of 33 students elected a class treasurer. There were 11 votes for Candidate A and 15 votes for Candidate B. The remainin

vovangra [49]

To start out, notice that you want the percent of voters that chose candidate A, not the percent of the class that chose candidate A.

Your fraction should be "number that chose candidate A" out of "number of voters," which is the same thing as saying:
"number that chose candidate A" divided by "number of voters"

1) The numerator of the fraction should be the number of votes for candidate A, which is 11.

2) The denominator of the fraction should be the number of voters. You're told that "t<span>here were 11 votes for Candidate A and 15 votes for Candidate B," so there are:
</span> $11 + 15 \: total \: votes$

3) Finally put parts 1 and 2 together into a fraction and multiply by 100 to get your percent. That is your final answer:
$\frac{11}{11+15} \times 100$

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Answer: Top right choice, $\frac{11}{11+15} \times 100$
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5 0

3 years ago

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then