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erik [133]
2 years ago
7

What is the value of x if x =3^2​

Mathematics
1 answer:
ycow [4]2 years ago
5 0

Answer:

9

Step-by-step explanation:

Raise 3 to the power of 2.

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John ordered five large size pizzas for a party. Five kids each ate 1/10 slice, and twelve adults each at 3/10 slices.
astraxan [27]

Answer:

a) 4 1/10 slices eaten

b) cannot be solved because we don't know how many slices in each pizza

Step-by-step explanation:

5*1/10=5/10

12*3/10=36/10

36/10+5/10=41/10

41/10=4 1/10 slices

8 0
3 years ago
Perform the indicated operation. 6 - 2i/5 + 3i =
fgiga [73]
I am gonna assume it is C)9/4 - 1/2i
5 0
3 years ago
Read 2 more answers
Can anyone help solve this for me ASAP. Thanks!
Anuta_ua [19.1K]

Answer:

x = 20

y = 26

Step-by-step explanation:

40 and 2x are vertical angles, so they're equal to each other.

40 = 2x

Divide both sides by 2

x = 20

We see that 40 and 5y + 10 are a linear pair, which means they add up to 180.

5y + 10 + 40 = 180

5y + 50 = 180

5y = 130

y = 26

8 0
2 years ago
In a class of 40 students, 5 like neither Nokia nor
Vikki [24]

Answer:

No student liked only Nokia

Step-by-step explanation:

The information can be illustrated as shown on the Venn diagram.

The number of students who liked only Nokia is x.

The sum of all regions in the Venn diagram should be 40.

We add all to get:

5 + 5 + 30 + x = 40

40 + x = 40

x = 40 - 40

x = 0

Therefore no one liked only Nokia

8 0
2 years ago
3.11 A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the nu
djverab [1.8K]

Answer:

Probability distribution for x:

P(x=0)=0.3644\\\\P(x=1)=0.4373\\\\P(x=2)=0.1749\\\\P(x=3)=0.0233\\\\

Step-by-step explanation:

We can model the number of defective sets in the group of TV sets (variable x) as a binomial variable, with sample size=3 and probability of success p=2/7≈0.2857.

The probability of k defective sets in the group is:

P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}

So, we have this probabilty distribution for x:

P(x=0) = \dbinom{3}{0} p^{0}q^{3}=1*1*0.3644=0.3644\\\\\\P(x=1) = \dbinom{3}{1} p^{1}q^{2}=3*0.2857*0.5102=0.4373\\\\\\P(x=2) = \dbinom{3}{2} p^{2}q^{1}=3*0.0816*0.7143=0.1749\\\\\\P(x=3) = \dbinom{3}{3} p^{3}q^{0}=1*0.0233*1=0.0233\\\\\\

7 0
3 years ago
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