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Anarel [89]
3 years ago
15

- If f ( x ) = x² + 2x - 1 and g ( x ) = 3x - 2 , then verify the following :

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Step-by-step explanation:

Hey there!

Given;

f ( x ) = x² + 2x - 1

g ( x ) = 3x - 2

To verify:

( \frac{f}{g} )(2) =  \frac{f(2)}{g(2)}

LHS:

(\frac{f}{g} )(x) =  \frac{ {x}^{2}  + 2x - 1}{3x - 2}

~ Insert "2" instead of "x".

(\frac{f}{g} )(2) =  \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}

Simplify it;

\frac{f}{g} (2) =  \frac{4 + 4 - 1}{6 - 2}

Therefore; (f/g)(2) = 7/4.

RHS:

\frac{f(x)}{g(x)}  =  \frac{ {x}^{2}  + 2x - 1}{3x - 2}

~Insert "2" instead of"x".

\frac{f(2)}{g(2)}  =  \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}

Simplify it.

\frac{f(2)}{g(2)}  =  \frac{4 + 4 - 1}{6 - 2}

Therefore, f(2)/g(2) = 7/4.

Since (f/g)(2) = f(2)/g(2) = 7/4.

<em><u>Proved!</u></em>

<u>Hope </u><u>it </u><u>helps</u><u>!</u>

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8_murik_8 [283]

Using the segment addition theorem, the solutions are:

5. x = 17

6. x = 7

7. x = 14

BC = 27

CD = 61

BD = 88

8. AB = 26

9. LJ = 46

10. x = 3

11. FG = 15

12. QS = 34

13. BC = 26

14. EG = 19

15. QS = 68

<h3>How to Apply the Segment Addition Theorem?</h3>

The segment addition theorem would be used to solve the problems as shown below:

5. UW = UV + VW [segment addition theorem]

Substitute

6x - 35 = 19 + 4x - 20

6x - 4x = 35 + 19 - 20

2x = 34

x = 17

6. HJ = HI + IJ [segment addition theorem]

Substitute

7x - 27 = 3x - 5 + x - 1

7x - 3x - x = 27 - 5 - 1

3x = 21

x = 7

7. BD = BC + CD [segment addition theorem]

Substitute

7x - 10 = 4x - 29 + 5x - 9

7x - 4x - 5x = 10 - 29 - 9

-2x = -28

x = 14

BC = 4x - 29 = 4(14) - 29 = 27

CD = 5x - 9 = 5(14) - 9 = 61

BD = 7x - 10 = 7(14) - 10 = 88

8. BC = BD

Substitute

2x + 1 = 5x - 26

2x - 5x = -1 - 26

-3x = -27

x = 9

AB = 43 - BC

AB = 43 - 2x + 1 = 43 - 2(9) + 1 = 26

9. 7x - 10 = 9x - 11 - (x + 3)

7x - 10 = 9x - 11 - x - 3

7x - 9x + x = 10 - 11 - 3

-x = -4

x = 4

LJ = 28 + 7x - 10 = 28 + 7(4) - 10

LJ = 46

10. 8x + 11 = 12x - 1

8x - 12x = -11 - 1

-4x = -12

x = 3

11. 11x - 7 = 3x + 9

11x - 3x = 7 + 9

8x = 16

x = 2

FG = 11x - 7 = 11(2) - 7

FG = 15

12. 5x - 3 = 21 - x

5x + x = 21 + 3

6x = 24

x = 4

QS = 2(5x - 3) = 10x - 6 = 10(4) - 6

QS = 34

13. 8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

8x - 6x = 20 - 2

2x = 18

x = 9

BC = AB = 3x - 1 = 3(9) - 1

BC = 26

14. 5x - 1 = 7x - 13

5x - 7x = 1 - 13

-2x = -12

x = 6

EG = 6x - 4 - 13 = 6(6) - 4 - 13

EG = 19

15. RT - ST = RS

Substitute

8x - 43 - (4x - 1) = 2x - 4

8x - 43 - 4x + 1 = 2x - 4

4x - 42 = 2x - 4

4x - 2x = 42 - 4

2x = 38

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QS = 2(RS)

QS = 2(2x - 4) = 4x - 8 = 4(19) - 8

QS = 68

Learn more about the segment addition theorem on:

brainly.com/question/28263183

#SPJ1

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How do I do this? I need it in perimeter to 2 decimal places. Thank you!
ad-work [718]

Answer:

The perimeter is 127.1 cm

Step-by-step explanation:

30+25+25=80

(2)(3.14)(15)=94.2

94.2/2=47.1

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Answer:

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Step-by-step explanation:

Your equation:

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Step 1: Simplify both sides of the equation.

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Step 2: Subtract 21x-28 from both sides.

x^2+24x−26−(21x−28)=21x−28−(21x−28)

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Step 3: Factor left side of equation.

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Step 4: Set factors equal to zero.

x+1=0 or x+2=0

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Answer:

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1 4/6 + 6/7

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1 4/6 6x1= 6+4= 10/6

Simplify 10/6 --> 5/3

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Answer and Step-by-step explanation:

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