Question

- If f ( x ) = x² + 2x - 1 and g ( x ) = 3x - 2 , then verify the following :

Answer 1

Step-by-step explanation:

Hey there!

Given;

f ( x ) = x² + 2x - 1

g ( x ) = 3x - 2

To verify:

$( \frac{f}{g} )(2) = \frac{f(2)}{g(2)}$

LHS:

$(\frac{f}{g} )(x) = \frac{ {x}^{2} + 2x - 1}{3x - 2}$

~ Insert "2" instead of "x".

$(\frac{f}{g} )(2) = \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}$

Simplify it;

$\frac{f}{g} (2) = \frac{4 + 4 - 1}{6 - 2}$

Therefore; (f/g)(2) = 7/4.

RHS:

$\frac{f(x)}{g(x)} = \frac{ {x}^{2} + 2x - 1}{3x - 2}$

~Insert "2" instead of"x".

$\frac{f(2)}{g(2)} = \frac{ {2}^{2} + 2 \times 2 - 1 }{3 \times 2 - 2}$

Simplify it.

$\frac{f(2)}{g(2)} = \frac{4 + 4 - 1}{6 - 2}$

Therefore, f(2)/g(2) = 7/4.

Since (f/g)(2) = f(2)/g(2) = 7/4.

Proved!

Hope it helps!