First write an equation system based on the problem
We can write "<span>Bread and sugar cost 110 together" as
</span>∴ b + s = 110
We can write "<span>bread cost 100 more than sugar" as
</span>∴ b = 100 + s
<span>
Second, solve the equation system by subtitution method
Subtitute b with (100+s) in the first equation, and we'll find the value of s
b + s = 110
(100 + s) + s = 110
100 + 2s = 110
2s = 110 - 100
2s = 10
s = 10/2
s = 5
The cost of the sugar is 5</span>
It’s add positive 2 every time I believe
if I’m wrong I’m so sorry and please tell me I’m wrong for other that have to use this.
If I’m right ya!! XD
Hope this helps you!
-Pam Pam
Time = distance / rate
time = 290 / rate
a) 3(-2) + 4(3) = -6 + 12 = 6
b) 2(-2) -3(3) +5 = -4 -9 + 5 = -8
c) 4(-2) -(3) = -8 -3 = -11
d) -(-2) -2(3) = 4 -6 = -2
e) (1/2)(-2) +(3) = -1 +3 = 2
f) (2/3)(3) -(1/2)(-2) = 2 + 1 = 3
If you send me the points I’ll do it in the comments
