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docker41 [41]
3 years ago
12

To find an estimate for  π I could...

Mathematics
2 answers:
11111nata11111 [884]3 years ago
6 0

Answer:

You could use 3.14 or 22/7

Step-by-step explanation:

It should be what you're asking, if not, tell me and I'll give you another answer.

:)

ArbitrLikvidat [17]3 years ago
3 0

Answer:

use 22/7 or 355/133, but 355/133 is not very commonly used and is unwieldy.

Step-by-step explanation:

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What type of angles are 1 and 8
Iteru [2.4K]

Answer:

Alternate exterior angles

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3 years ago
Help please!!! Find the sum of the series show your work
AleksAgata [21]

Answer:

\sum_{i=1}^{12}(3i-1) = 222

Step-by-step explanation:

The given series is

\sum_{i=1}^{12}(3i-1)

The first term is

f(1) = 3 \times 1 - 1 = 2

The last term is

f(12) = 3 \times 12 - 1 = 35

To find the number of terms in the sequence, solve,

3i - 1 = 35

3i = 36 \\ i = 12

The sum of the first i-terms of an arithmetic sequence is:

S_i =  \frac{i}{2} (f(1) + f(2))

We substitute the values to get;

S_ {12}=  \frac{12}{2} (2+ 35)

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6 0
4 years ago
The point ( -6 , 8 ) is reflected across the y axis. What is the coordinates of the reflection
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The new coordinations would be (6,8)

6 0
3 years ago
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Express 321,000,000,000 in scientific notation
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3.21 + 10 × 11

3.21 + {10}^{11}
6 0
4 years ago
Find an equation of the plane consisting of all points that are equidistant from (-3, 5, -4) and (-5, 0, 4), and having -2 as th
Firdavs [7]

Answer:

-2x-5y+8z+4.5=0

Step-by-step explanation:

Let (x,y,z) be the coordinates of the point lying on the needed plane. This point is equidistant from the points (-3, 5, -4) and (-5, 0, 4), so

d_1=\sqrt{(x-(-3))^2+(y-5)^2+(z-(-4))^2}=\sqrt{(x+3)^2+(y-5)^2+(z+4)^2}\\ \\d_2=\sqrt{(x-(-5))^2+(y-0)^2+(z-4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\d_1=d_2\Rightarrow \sqrt{(x+3)^2+(y-5)^2+(z+4)^2}=\sqrt{(x+5)^2+y^2+(z-4)^2}\\ \\(x+3)^2+(y-5)^2+(z+4)^2=(x+5)^2+y^2+(z-4)^2\\ \\x^2+6x+9+y^2-10y+25+z^2+8z+16=x^2+10x+25+y^2+z^2-8z+16\\ \\-4x-10y+16z+9=0\\ \\-2x-5y+8z+4.5=0

5 0
3 years ago
Read 2 more answers
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