10x8=80 dollars that day
80+30=$110
Hope this helps!! Have a good day
Answer:
It would take 336 seconds
Step-by-step explanation:
Set up as a proportion:
50 meters/21 seconds = 800 meters/x
Then we cross multiply to find the answer:
336 = x
Answer:
The speed of Kali is 30 mph.
Step-by-step explanation:
Let, the speed of Kali be "x", then speed of Ndiba will be:
Speed of Ndiba = x + 15 mph
If, the time for travel for Ndiba is 2 hrs, when he catches Kali, and he left 1 hour later than Kali, then then time traveled by Kali at that instant will be 2+1 = 3hrs.
At the point of meeting both will have covered same distance.
Distance Covered by Kali = Distance Covered by Ndiba
(Speed of Kali)(Time traveled by Kali) = (Speed of Ndiba)(Time traveled by Ndiba)
(x)(3) = (x +15)(2)
3x = 2x +30
<u>x = 30 mph</u>
The correct answer is, actually 30 mph, by the solution shown above.
Answer:
To do this, subtract 6 from both sides. − 3_x_ + 6 − 6 > 12 − 6. −3_x_ > 6. Now divide both sides of the inequality by −3. Since you're dividing by a negative number, you need to flip the inequality sign.
Step-by-step explanation:
Answer:
The probability that a manufactured ball will be rejected is 0.99, to two decimal places.
Step-by-step explanation:
The mean weight is 16 Ibs. The standard deviation of the weights of all manufactured balls from the mean weight is 25. The distribution is normal. With a standard deviation this large, it is already obvious that there is a high probability of producing or having rejected balls. The weights of the balls produced here ranges from (16-25)Ibs to (16+25)Ibs.
That's -9Ibs to 41Ibs.
The minimum permissible weight is 15.68. Any ball with a lesser weight gets kicked out!
So the distance or difference between this figure and the mean is (16-15.68) = 0.32
So the probability of obtaining less than 15.68Ibs or the probability of having balls between the lower boundary of -9Ibs and 15.68 is:
25-0.32 = 24.68
24.68 ÷ 25 = 0.9872 ~ 0.99 to two decimal places.
