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eduard
3 years ago
14

Steven and Julio each have 13 marbles. Megan has twice the number of marbles as Steven and Julio combined. Steven thinks that me

ans that Megan has 26 marbles. What is an estimate of the number of marbles that Megan has? Is 26 a reasonable total? 13; 26 is a reasonable total 50; 26 is not a reasonable total 169; 26 is a reasonable total 338; 26 is not a reasonable total
Mathematics
1 answer:
kodGreya [7K]3 years ago
6 0

Answer:

50

Step-by-step explanation:

Steven = 13 marbles

Julio = 13 marbles

Megan has twice the number of marbles as Steven and Julio combined

Megan = 2 (13 + 13) = 2(26) = 52 marbles

Among the options (26, 13, 50, 169, 338), the only reasonable estimate is 50

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Elderly drivers. In January 2011, The Marist Poll published a report stating that 66% of adults nationally think licensed driver
katrin [286]

Answer:

(a) Hence, the margin of error reported by The Marist Poll was correct.

(b) Based on a 95% confidence interval the poll does not provide convincing evidence that more than 70% of the population think that licensed drivers should be required to retake their road test once they turn 65.

Step-by-step explanation:

We are given that the Marist Poll published a report stating that 66% of adults nationally think licensed drivers should be required to retake their road test once they reach 65 years of age.

It was also reported that interviews were conducted on 1,018 American adults, and that the margin of error was 3% using a 95% confidence level.

(a) <u>Margin of error formula is given by;</u>

             Margin of Error =  Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  

where, \alpha = level of significance = 1 - 0.95 = 0.05 or 5%

Standard of error =  \sqrt{\frac{\hat p(1-\hat p)}{n} }

Also, \hat p = sample proportion of adults nationally think licensed drivers should be required to retake their road test once they reach 65 years of age = 66%

n = sample of American adults = 1.018

The critical value of z for level of significance of 2.5% is 1.96.

So, <em>Margin of Error </em>=  Z_(_\frac{\alpha}{2}_)  \times \sqrt{\frac{\hat p(1-\hat p)}{n} }  

                                =  1.96  \times \sqrt{\frac{0.66(1-0.66)}{1,018} } = 0.03 or 3%

Hence, the margin of error reported by The Marist Poll was correct.

(b) Now, the pivotal quantity for 95% confidence interval for the population proportion who think that licensed drivers should be required to retake their road test once they turn 65 is given by;

                   P.Q. =  \frac{\hat p-p}{ \sqrt{\frac{\hat p(1-\hat p)}{n} }}  ~ N(0,1)

So, <u>95% confidence interval for p</u> =  \hat p \pm \text{Margin of error}

                                                        =  0.66 \pm 0.03

                                                        =  [0.66 - 0.03 , 0.66 + 0.03]

                                                        =  [0.63 , 0.69]

Hence, based on a 95% confidence interval the poll does not provide convincing evidence that more than 70% of the population think that licensed drivers should be required to retake their road test once they turn 65 because the interval does not include the value of 70% or more.

7 0
3 years ago
A study show that there are 16 vehicles for every 10 households how many vehicles are there for 107 million households
Lisa [10]
\bf \begin{array}{ccll}&#10;vehicles&households\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;16&10\\&#10;v&107E6&#10;\end{array}\implies \cfrac{16}{v}=\cfrac{10}{17E6}\implies \cfrac{17E6\cdot 16}{10}=v

just to clarify the engineering notation, E6 is just 1 and 6 zeros, or a million, thus, 107,000,000 is just 107E6.
6 0
3 years ago
What is 5C3?<br> A. 35<br> B. 10<br> C. 14<br> D. 28
galben [10]

Answer: B. 10

-5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time. To calculate combinations, we will use the formula nCr = n! / r! ... * (n - r)!, where n represents the total number of items, and r represents the number of items being chosen at a time.

-10 is the total number of all possible combinations for choosing 3 elements at a time from 5 distinct elements without considering the order of elements in statistics & probability surveys or experiments. The number of combinations for sample space 5 CHOOSE 3 can also be written as 5C3 in the format of nCr or nCk.

Step-by-step explanation: Hope this help :D

5 0
2 years ago
Read 2 more answers
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NikAS [45]

Answer:

parallel

Step-by-step explanation:

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2 years ago
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Evaluate the expression for k = 2. –9 + 7k =
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Answer:

k = 7/6

Step-by-step explanation:

8 0
2 years ago
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