If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.
So, what are the chances of it not occurring in 1 trip?
1−.37=.63
What about not occurring in 2 trips?
(1−.37)⋅(1−.37)=.63⋅.63=.3969
Now what about not occurring in 4 trips?
.63^4 = 0.15752961
We must subtract this value from 1
(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:
1−0.15752961 = .84247039
TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.
-0.7 - (-2.5) =
-0.7 + 2.5 =
2.5 - 0.7 = 1.8
1.8 is your answer
hope this helps
Answer: A
Step-by-step explanation:
<u>Answer</u>
6,122 hm
<u>Explanation</u>
You can carry out operations on the like terms only. So convert all units to one unit.
I will convert them to dam
1 km =100 dam
73 km = 73 × 100
=7,300 dam
11 km = 11× 100
1100 dam
1 hm = 10 dam
47 hm = 47 × 10
= 470 dam
55 hm = 55× 10
= 550 dam
73km 47hm 2dam - 11km 55hm = (7300+ 470+2) - (1100+550)
= 7,772 - 1,650
= 6,122 hm
Answer:
5) 64
3) a loaf of bread
6) 2
4) see saw
Step-by-step explanation:
