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Jlenok [28]
3 years ago
11

8x - 5x - 1 = 11 - 2x

Mathematics
2 answers:
diamong [38]3 years ago
8 0

Answer: x=12/5

Step-by-step explanation:

Combine like terms first:

3x-1=11-2x

Get both x terms on the same side and combine them:

5x-1=11

Isolate the x variable:

X=12/5

larisa86 [58]3 years ago
8 0
<h3>Given :</h3>

  • 8x - 5x - 1 = 11 - 2x

<h3>To Find :</h3>

  • Value of x = ?

<h3>Solution :</h3>

\sf \dashrightarrow 8x - 5x - 1 = 11 - 2x

\sf \dashrightarrow 3x - 1 = 11 - 2x

\sf \dashrightarrow 3x - 1 - 11 + 2x = 0

\sf \dashrightarrow 5x - 12 = 0

\sf \dashrightarrow 5x = 12

\sf \dashrightarrow x = \dfrac{12}{5}

Hence, value of x is 12/5.

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In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
When the area in square units of an expanding circle is increasing twice as fast as its radius in linear units
alexira [117]

Answer:

r=1/π

Step-by-step explanation:

Area of the circle is defined as:

Area = πr²

Derivating both sides

\frac{dA}{dr}=2πr

\frac{dA}{dt}  =  \frac{dA}{dr} x \frac{dr}{dt}  =  2πr\frac{dr}{dt}

If area of an expanding circle is increasing twice as fast as its radius in linear units. then we have : \frac{dA}{dt}  =2\frac{dr}{dt}

Therefore,

2πr \frac{dr}{dt}  =  2  \frac{dr}{dt}

r=1/π

5 0
3 years ago
Read 2 more answers
approximate each irrational number to the nearest hundredth without using a calculator square root of 118 and 319​
Strike441 [17]

Answer:

\sqrt{118}\approx 10.86

\sqrt{319}\approx 17.86

Step-by-step explanation:

Consider the provided number.

We need to find the approximate value of \sqrt{118} to the nearest hundredth.

First find two perfect squares that the irrational number falls between.

100

118 is lying between 100 and 121, therefore the square root value of 118 will be somewhere between 10 and 11.

\sqrt{100}

10

118 is closer to 121 as compare to 100.

Therefore, \sqrt{118}\approx 10.86

Consider the number \sqrt{319}

First find two perfect squares that the irrational number falls between.

289

319 is lying between 289 and 324, therefore the square root value of 319 will be somewhere between 17 and 18.

\sqrt{289}

17

319 is closer to 324 as compare to 289.

Therefore, \sqrt{319}\approx 17.86

8 0
3 years ago
Please help with the question,
castortr0y [4]
The correct answer is x^2-2x+2=0

 The explanation is shown below:

 1. To solve the problem shown in the figure above, you must apply the following proccedure:

 2. You have that the roots of the quadratic equation shown in the figure attached in the problem are:

  x=-1±i

 3.  Then, you know the quadratic formula to solve quadratic equations, which is:

 (-b±√(b^2-4ac))/2a

 4. You can see in the figure that a=1 and c=2; then, by analizing this, you can conclude that the coefficient b is:

 b=-2

 5. Therefore, you can conclude tha the quadratic equation is:

 x^2-2x+2=0

 6. If you want to verify it, apply the quadratic formula to the quadratic equation shown above and you will obtain the roots shown in the figure.
8 0
3 years ago
Read 2 more answers
Is the relation a function? If so why or why not? {(-3,2),(-1,0),(1,0),(5,-2)}
Anastasy [175]

Answer:

It's a function

Step-by-step explanation:

Functions can only have one output for each input. And since all the x values for each point are different, there is only one output (y-value) for each input(x-value).

8 0
3 years ago
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