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KiRa [710]
3 years ago
11

Ron walks 22.5 in 5 hours finds his speed​

Mathematics
1 answer:
Lostsunrise [7]3 years ago
7 0

Answer:

his speed would be 4.5 miles per hour

Step-by-step explanation:

if you do the distance divided by the hours you will get the answer.

  22.5/5=4.5

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On Friday,a museum had 185 visitors. On Saturday,there were twice as many visitors as Friday. On Sunday,50 fewer people visited
RoseWind [281]
Friday - 185

Saturday - 185 x 2
= 370

Sunday - 370 - 50
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3 years ago
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Please help i will mark brainliest
Mariana [72]

Answer:

6/11

Step-by-step explanation:

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2 years ago
The legs of an isosceles right triangle are 5 inches long. What is the length of the hypotenuse of the triangle to the nearest i
In-s [12.5K]
The legs are 5 inches long.

Use the Pythagorean theorem:
5^2+5^2=c^2 \\
25+25=c^2 \\
50=c^2 \\
c=\sqrt{50} \\
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The length of the hypotenuse of the triangle is approximately 7 inches long.
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3 years ago
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Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
2 years ago
Please and don’t just answer for the points, it’s rude
Artyom0805 [142]

Answer:

7a ( 1,1)

7b ∅  or no solution

Step-by-step explanation:

The solution to the system is where the two functions intersect

For 7a.  The parabola and the line intersect at (1,1)

For 7b  The parabola and the line do not intersect so there is no solution

3 0
3 years ago
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