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r-ruslan [8.4K]
3 years ago
12

Please help as soon as possible. Thank you

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer:

14.96 X 35% = 5.24 So take the 14.96 and subtract the 5.24 = $9.72 Is The Anwser

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Helpppp me please!! I dont understand.
Dafna1 [17]

Answer:

X = 11

X = 7

Step-by-step explanation:

Part 1:

The measure of an inscribed angle is half the measure of an intercepted arc. So 1/2 mCE = m∠CDE

158 ÷ 2 = 79

You need to find x so you're going to set your equation of (8x - 9) = 79

Then you're going to add 9 to both sides to get 8x = 88

Divide both sides by 8 to get x = 11

Part 2:

We know that WY is 180 because it's a semicircle. Using this and the knowledge that ∠WXY is half the measure of the intercepted arc (180), we know that our equation should be (13x - 1) = 90

add 1 to both sides and our equation is (13x = 91)

Divide both sides by 13 and...

x = 7

8 0
3 years ago
Read 2 more answers
Solve the following linear equation for k.<br> 2 (k-5) + 3k = k + 6
kiruha [24]

Answer:

2(k-5)+3k=k+6

-3k. -3k

2(k-5)=-2k+6

/2. /2

k-5=-k+3

+k. +k

2k-5=3

+5. +5

2k=8

/2. /2

k=4

7 0
2 years ago
What multiplies to 16 and adds to negative 12
Romashka-Z-Leto [24]
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm


we will solve with math
xy=16
x+y=-12
minus  x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}


0=x^2+12x+16
a=1
b=12
c=16

x=\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}
x=\frac{-12+/- \sqrt{144-64 }}{2}
x=\frac{-12+/- \sqrt{80}}{2}
x=\frac{-12+/- 4\sqrt{5}}{2}
x=\frac{-6+/- 2\sqrt{5}
x=\frac{-6+ 2\sqrt{5} or \frac{-6- 2\sqrt{5}

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0
3 years ago
Read 2 more answers
⚠️‼️ HELP PLEASE GIVING POINTS !!​
vitfil [10]

Answer:

m∠QPR = 25°.

Step-by-step explanation:

If m∠QPR = 9x + 16°, substitute in 1 for 'x':. 9(1) + 16 = 9 + 16 = 25°

7 0
1 year ago
Which expression is equivalent to sec^2x − 1? a. cot2x b. tan2x c. csc2x d. cos2x
Nesterboy [21]
Sec^2 x - 1 = tan^2x

Proof:
Sec^2x = 1+ tan^2x

1/cos^2x = 1 + sin^2x/cos^2x

<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting : 
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side 
4 0
2 years ago
Read 2 more answers
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