Answer:
X = 11
X = 7
Step-by-step explanation:
Part 1:
The measure of an inscribed angle is half the measure of an intercepted arc. So 1/2 mCE = m∠CDE
158 ÷ 2 = 79
You need to find x so you're going to set your equation of (8x - 9) = 79
Then you're going to add 9 to both sides to get 8x = 88
Divide both sides by 8 to get x = 11
Part 2:
We know that WY is 180 because it's a semicircle. Using this and the knowledge that ∠WXY is half the measure of the intercepted arc (180), we know that our equation should be (13x - 1) = 90
add 1 to both sides and our equation is (13x = 91)
Divide both sides by 13 and...
x = 7
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=

0=x^2+12x+16
a=1
b=12
c=16
x=

x=

x=

x=

x=

x=

or

aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721
Answer:
m∠QPR = 25°.
Step-by-step explanation:
If m∠QPR = 9x + 16°, substitute in 1 for 'x':. 9(1) + 16 = 9 + 16 = 25°
Sec^2 x - 1 = tan^2x
Proof:
Sec^2x = 1+ tan^2x
1/cos^2x = 1 + sin^2x/cos^2x
<span>1/cos^2x - sin^2x/cos^2x = 1
</span>Using common denominator:
(1-sin^2x)/cos^2x = 1
sin^2x + cos^2 x = 1
cos^2 x = 1 - sin^2x
Substituting :
cos^2x/<span>cos^2x = 1
</span>1 = 1
Left hand side = right hand side