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Alexus [3.1K]
3 years ago
6

Solve the triangle give the measure of y

Mathematics
1 answer:
pishuonlain [190]3 years ago
4 0

Given:

In triangle BGU,BG=x,GU=7,BU=y,m\angle U=90^\circ,m\angle B=44^\circ.

To find:

The value of y.

Solution:

In a right angle triangle,

\tan \theta=\dfrac{Perpendicular}{Base}

In triangle BGU,

\tan B=\dfrac{GU}{BU}

\tan 44^\circ=\dfrac{7}{y}

0.966=\dfrac{7}{y}

Isolating y, we get

y=\dfrac{7}{0.966}

y=7.2463

y\approx 7.2

Therefore, the correct option is A.

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Brandon and Jerry like to play video games. Brandon has vvv video games, and Jerry has 292929 video games. Together they have a
lianna [129]

Answer:

444,444

Step-by-step explanation:

total amount=737373

jerry=292929

Brandon=unknown

To figure the amount of video games Brandon has, we have to subtract the amount of both he and his friend altogether amount with Jerry's current amount of video games.

737,373-292,929=444,444

So, by subtracting the two, the answer would be 444,444.

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5 0
3 years ago
How many area codes (abc) would be possible if all three digits could be any vaiue 1-9
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Answer:

<u>The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.</u>

Step-by-step explanation:

1. Let's start our reasoning to get this answer:

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

<u>Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:</u>

<u>1,000 - 100 - 19 - 152 = 729</u>

<u>The simplest way to find it, is:</u>

<u>For 000 to 999 = 1,000 or 10³</u>

<u>Excluding the digit zero = 729 or 9³</u>

3 0
3 years ago
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In this question,it is given that,

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And in the next part it is given that , volume is 7700 cubic meters and height is 148 meters .

Substituting these values, we will get

s = \sqrt{ \frac{3V}{h}}&#10;\\&#10;s = \sqrt{ \frac{3*7700}{148}} = 12.5 meters

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4 years ago
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Answer:

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The following lock needs a correct 4 digit passcode to open.
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The answer for this question is 12 56
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