We are given a line segment with two points on each end. Rebecca draws two arcs with equal radius from each point. Now, the intersection of the two arcs is the midpoint of the line. This can be explained by the radius of the arcs. Since they are equal, meaning they have the same distance from each point. Thus, the midpoint of the line.
Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Since every side of a square is the same length, and the formula to find the area is bh you would just do 2.75²
2.75×2.75=7.5625≈7.56
the answer is the area of the square is approximately 7.56u²
Answer:
7
Step-by-step explanation:
22+54x=20+60x
54x=-42+60x
-6x=-42
x=7