Answer:
- <u><em>The solution to f(x) = s(x) is x = 2012. </em></u>
Explanation:
<u>Rewrite the table and the choices for better understanding:</u>
<em>Enrollment at a Technical School </em>
Year (x) First Year f(x) Second Year s(x)
2009 785 756
2010 740 785
2011 690 710
2012 732 732
2013 781 755
Which of the following statements is true based on the data in the table?
- The solution to f(x) = s(x) is x = 2012.
- The solution to f(x) = s(x) is x = 732.
- The solution to f(x) = s(x) is x = 2011.
- The solution to f(x) = s(x) is x = 710.
<h2>Solution</h2>
The question requires to find which of the options represents the solution to f(x) = s(x).
That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.
The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012,<em> x = 2012. </em>
Thus, the correct choice is the third one:
- The solution to f(x) = s(x) is x = 2012.
Answer:
3/10
Step-by-step explanation:
Let's assume;
30 ml of Orange Juice + 45 ml of Apple Juice + 25 ml of Coconut milk = 1 glass of Cocktail
30 ml : 45 ml : 25 ml = 1
30 + 45 + 25 = 100 ml = 1 glass of Cocktail
Orange juice proportion = Amount of Orange Juice in ml ÷ 1 glass of Cocktail in ml
Orange Juice proportion = 30 ml ÷ 100 ml
= 3/10
Answer:
6(9r-7)
Step-by-step explanation:
54r–42
Both 54 and 43 can be divided by 6
54/6 =9 and 42/6 =7
6*9r - 6*7
Factor out the 6
6(9r-7)
Answer:
A.16–i is correct.
Step-by-step explanation:
(4+i)(4–i). [(a+b)(a–b)=(a²–b²)]
(4²–i²)=16–i
I hope this answer is correct so please vote my answer
Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.
We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.
Given, π = 3.14
Beaker 1:
Radius (r₁) = 2 cm
Height (h₁) = 3 cm
Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³
Beaker 2:
Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³
Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³
