A) > since it is 50c per weekday and 75c each weekend assuming it allows for the 2 days each saturday/sunday.
50c * 5 = $2.50 since there are 5 days in weekdays
75c * 2 = $1.50 since there are 2 days in the weekend
Add $2.50 and $1.50 to get $4.00
b) For 3 school days we know it is a weekday on the school week.
So perform 50c * 3 which gives us <span>$1.50
</span>c) 12 days off from school is 10 weekdays and 1 weekend or 2 days of 75c
So now just do 50c * 10 which is $5.00 and 75c * 2 which is $1.50
Add $5.00 and $1.50 and we get $6.50
d) 4 weeks = 20 weekdays since 5 *4 = 20 and 8 days in each weekend since 2 * 4 = 8
Now that we have the amount of weekdays and weekend days we can multiply.
50c * 20 = $10.00
75c * 4 = $3.00
Add $10.00 and $3.00 to get $13.00 for 4 weeks.
e) We have 1 day of the weekend and 2 weekdays here.
50c * 2 = $1.00
75c * 1 = 75c
<span>$1.00 + 75c = $1.75 in those 3 days listed.
</span>
Add all these together to get your total value.
$4.00 + $1.50 + $6.50 + $13.00 + $1.75 = $26.75
You are solving for the height. Use the formula:
c² - b² = a² in which c = hypotenuse
(13)² - (5)² = a²
Simplify
169 - 25 = a²
144 = a²
Isolate the a. Root both sides
√144 = √a²
a = √144
a = √(12 x 12)
a = 12
C) 12 feet is your answer
~
Given:
Amount = Rs. 9,144
Time = 3 years.
Rate of simple interest = 9%
To find:
The principal value.
Solution:
The formula for simple interest is:
Where, P is principal, r is the simple rate of interest, and t is the number of years.
Putting 
in the above formula, we get
We know that,
Divide both sides by 1.27, we get
Therefore, the principal value is Rs. 7200.
Answer:265.25
Step-by-step explanation:
Given
Volume of box
height is 3 times the width
let height, length and breadth be H, L & B
4=B^2\times L[/tex]
Cost of side walls $ 
Cost of base $ 
Cost of side walls
Cost of base 
Total cost 
differentiate C w.r.t B to get minimum cost
L=2.19 m
C=$ 265.25
