Answer:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
- d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
- After first dose residual drug amount is:
d= 500*0.045= 22.5 mg
- After second dose:
d= 22.5*2= 45 mg
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
for the second column it is 12.5
for the third column it is 20%
for the fourth column it is 120%
for the fifth column it is 33%
for the sixth column it is 11.35
for the seventh column it is 900
for the 8th column it is 60%
for the final column it's 39
Step-by-step explanation:
Answer:
d. (2, -4)
Step-by-step explanation:
The equation describes a circle centered at (2, -3) with a radius of 2.
Any points with an x-coordinate of 2 must have a y-coordinate in the interval -3±2 = (-1, -5) to be inside the circle. One such point is ...
(2, -4) . . . . choice D
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The attached graph shows the locations of the answer choices.
Answer:
4
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given
= 11 +(n - 1)4 , then
d = 4
The recursive formula allows a term in the sequence to be found by adding d to the previous term, thus
=
+ 4