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Sedbober [7]
4 years ago
8

4 boxes can hold 40 books how many books per box

Mathematics
2 answers:
Lesechka [4]4 years ago
8 0
4x10=40
So there will be 10 books each 4 boxes
diamong [38]4 years ago
4 0

Answer:

10 books per box

Step-by-step explanation:

40÷4

=10

10×4= 40

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When solving the equation 5/18=5/4x+6 algebraically, it is possible to set the denominators of the fractions equal to each other
eduard

Yes, but only if the numerators of both fractions are equal to each other.

Given that two fractions are equal to each other, we can set the denominators to be equal to each other, in the instance of this question, but that is only possible, if and only if the numerators of the fractions are equal to one another.

Another proof is,

\frac{3}{9} = \frac{3}{4 + x}

like in the attached example, we can say that 9 = 4+x, and go further ahead to solve it.

9 = 4 + x

x = 9 - 4

x = 5

if x = 5, then we can assume that

\frac{3}{9} = \frac{3}{4 + 5}

\frac{3}{9} = \frac{3}{9}

This proves that only the numerator has to be the same for the denominator to be able to be equal to one another.

more explanation can be found here brainly.com/question/7067665

6 0
3 years ago
Read 2 more answers
3x +4y = - 23<br>2y - x = - 19<br>What is the solution (x, y) to the system of the equations <br>​
zloy xaker [14]

Answer:

all work is shown and pictured

6 0
3 years ago
Which matrix represents the vertices of the rectangle after it is scaled by a factor of 3?
bonufazy [111]

the awnser is C I just got it right

6 0
3 years ago
A Pew Research Center report on gamers and gaming estimated that 49% of U.S. adults play video games on a computer, TV, game con
Veseljchak [2.6K]

Using the z-distribution, it is found that the 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have that:

  • 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.
  • 49% out of 2001 U.S. adults play video games, hence \pi = 0.49, n = 2001.

The lower bound of the interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 - 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.4681

The upper bound of the interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 + 1.96\sqrt{\frac{0.49(0.51)}{2001}} = 0.5119

The 95% confidence interval for the proportion of all U.S. adults who play video games is (0.4681, 0.5119). It means that we are 95% sure that the true proportion of all U.S. adults who play video games is between 0.4681 and 0.5119.

To learn more about the z-distribution, you can take a look at brainly.com/question/25730047

5 0
3 years ago
3x-9 when x=3<br> Solve this
Citrus2011 [14]

Answer:

0

Step-by-step explanation:

3x - 9 if x = 3

Substitute:

3(3) - 9 =

9 - 9 = 0

This can be written as a function: f(x) = 3x - 9

f(3) = 3x - 9

f(3) = 3(3) - 9

f(3) = 9 - 9

f(3) = 0

-Chetan K

3 0
3 years ago
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