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4 years ago

What is 5 less than 15 as an expression

Mathematics

1 answer:

Aleonysh [2.5K]4 years ago

4 0

The phrase "5 less than" means we are subtracting 5 from some amount. And that amount is 15

So, 15 - 5 is the answer.

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Classify the following polynomials according to the number of terms. Combine any like terms first.

11Alexandr11 [23.1K]

1) Combining like terms, we get x^2 + 5x, which is a binomial.

2) Combining like terms, we get x^3 + 3x^2, which is a binomial.

3) Combining like terms, we get 4x^3 + x^2 - x, which is a trinomial.

4) I can't answer this because there's an asterisk in place of the exponent.

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3 years ago

Which expression is equivalent to this one?

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3 years ago

Jessie sorted the coins in her bank. She made 7 stacks of 6 dimes and 8 stacks of 5 nickels. She then found 1 dime and 1 nickel.

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3 years ago

1500 customers hold a VISA card; 500 hold an American Express card; and, 75 hold a VISA and an American Express. What is the pro

alex41 [277]

Answer:

There is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

$P(VISA \:| \:AE) = 15\%\\$

Step-by-step explanation:

Number of customers having a Visa card = 1,500

Number of customers having an American Express card = 500

Number of customers having Visa and American Express card = 75

Total number of customers = 1,500 + 500 = 2,000

We are asked to find the probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

This problem is related to conditional probability which is given by

$P(A \:| \:B) = \frac{P(A \:and \:B)}{P(B)}$

For the given problem it becomes

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}$

The probability P(VISA and AE) is given by

P(VISA and AE) = 75/2000

P(VISA and AE) = 0.0375

The probability P(AE) is given by

P(AE) = 500/2000

P(AE) = 0.25

Finally,

$P(VISA \:| \:AE) = \frac{P(VISA \:and \:AE)}{P(AE)}\\\\P(VISA \:| \:AE) = \frac{0.0375}{0.25}\\\\P(VISA \:| \:AE) = 0.15\\\\P(VISA \:| \:AE) = 15\%\\$

Therefore, there is 15% probability that a customer chosen at random holds a VISA card, given that the customer has an American Express card.

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3 years ago