10000 digits can be used for 4 digit A.T.M code.
<u>Solution:</u>
Given that A.T.M required 4 digit codes using the digits 0 to 9.
Need to determine how many four digit code can be used.
We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.
Now we have four places to be filled by 0 to 9 that is 10 numbers
Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .
First digit can be selected in 10 ways that is from 0 to 9.
After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.
So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways
Hence 10000 digits can be used for 4 digit A.T.M code.
Answer: The first graph.
This can be found by looking at the y-intercept and plugging in values for x.
Answer:
66 is the answer to your question
Answer:
44
Step-by-step explanation:
if 22 miles = 1/2
then, 22 times 2 = 44 miles
ANSWER= 44 miles
Answer:
The time the two planes will meet is 1.43 hours
Step-by-step explanation:
Given;
speed of the first plane in positive direction, = 40 mph
speed of the second plane in negative direction(opposite direction) = -100 mph
distance between the two planes = 200 miles
Let the time the two planes will meet = t
the position of the first plane at this time "t" = 40t
the position of the second plane at this time "t" = -100t
(40t)>--------------------------------<(-100t), this space between them is 200 miles.
Thus, the difference in the distance they traveled before meeting should be equal to 200 miles.
40t - (-100t) = 200
40t + 100t = 200
140t = 200
t = 200 / 140
t = 1.43 hours
Therefore, the time the two planes will meet is 1.43 hours
