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3 years ago

a line passes through the point -2 and five and has a slope of 2/3 points A(x,3) and B(-2,y)lie on the line

1 answer:

7 0

A and B lie on the line, yes, but what specifically are you supposed to do? Looks like your problem statement was cut off before you'd finished typing it in.

You say your line passes thru (-2,5) and has a slope of 2/3? Then, using the point-slope formula,

y-5 = (2/3)(x+2) This is the general equation for your line.

Now let's play around with B(-2,y). Suppose we subst. the x-coordinate of B, which is -2, into the equation y-5 = (2/3)(x+2); we get y-5 = (2/3)(-2+2) = 0. This tells us that y must be 5. But we already knew that!!

So, please review the original problems with its instructions and this discussion and tell me what you need to know from this point on.

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3 years ago

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FromTheMoon [43]

9514 1404 393

Answer:

(f×g)(x) = 2x^2 +2x
(f×g)(x) = 6y^2 -11y -35

Step-by-step explanation:

The distributive property applies.

1. (fg)(x) = f(x)·g(x) = (2x)·(x +1)

(f×g)(x) = 2x^2 +2x

2. (fg)(x) = f(x)·g(x) = (2y -7)·(3y +5) = 2y(3y +5) -7(3y +5)

(f×g)(x) = 6y^2 -11y -35

_____

<em>Additional comment</em>

Please note in problem 2 that the function argument is x and the variable in the given expressions is y. This means the function value is exactly and only <em>6y^2 -11y -35 for any value of x</em>. It does not change when x changes. (We suspect a typo.)

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3 years ago

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