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Rashid [163]
3 years ago
5

a line passes through the point -2 and five and has a slope of 2/3 points A(x,3) and B(-2,y)lie on the line

Mathematics
1 answer:
olasank [31]3 years ago
7 0
A and B lie on the line, yes, but what specifically are you supposed to do?  Looks like your problem statement was cut off before you'd finished typing it in.

You say your line passes thru (-2,5) and has a slope of 2/3?  Then, using the point-slope formula,

y-5 = (2/3)(x+2)  This is the general equation for your line.

Now let's play around with B(-2,y).  Suppose we subst. the x-coordinate of B, which is -2, into the equation   y-5 = (2/3)(x+2); we get y-5 = (2/3)(-2+2) = 0.  This tells us that y must be 5.  But we already knew that!!

So, please review the original problems with its instructions and this discussion and tell me what you need to know from this point on.



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Goshia [24]

Answer:

<h2>-1</h2>

Step-by-step explanation:

2x + 7  - 1 = 2x + 7

=  > 2x - 1 = 2x  + 7 - 7

=  > 2x - 1 = 2x

=  >  - 1 = 2x - 2x

=  > x =  - 1

7 0
2 years ago
A total of 8,644 people went to the football game. Of thos the visitors side. Of the people sitting on the visitor's side filled
lisov135 [29]
You divide 8644 by 8 which equals 1080.5, but since you can't have half of one person you approximate it to 1080 or 1081.
3 0
3 years ago
Find the slope. ASAP
vagabundo [1.1K]
The answer is number 4
3 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
A store sells a pair of boots for $125.80 after a 45% markup what was the cost to the store
ladessa [460]
125.8 times 0.45
it equals 56.61
i think so but i MIGHT be wrong
sorry if i am
4 0
2 years ago
Read 2 more answers
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