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IgorLugansk [536]
3 years ago
12

A basket of fruit contains 4 bananas, 3 apples, and 5 oranges. You intend to draw a piece of fruit from the basket, keep it, dra

w a 2nd piece of fruit from the basket, keep that, and then draw a third piece of fruit from the same basket.What is the probability of selecting one banana, then one apple, then one orange, in that order, from the basket if you are blindfolded?
Mathematics
1 answer:
gregori [183]3 years ago
4 0

Answer:

The probability that the fruits will be selected in the order of banana then apple then orange is 0.1094

Step-by-step explanation:

The given information are;

The number of bananas = 4

The number of apples = 3

The number of oranges = 5

The total number of fruits are 4 + 3 + 5 = 12

The probability of selecting a banana, p(b) = 4/12 = 1/3

The probability of selecting an apple, p(a) = 3/12 = 1/4

The probability of selecting an oranges, p(o) = 5/12

The probability of selecting one banana, then one apple, then one orange, in that order, from the basket with replacement is the product of the individual probabilities found as follows;

p(p(b) then p(a) then p(o)) =

The number o

The probability that the first fruit is a banana = ₁₁C₃×(1/3)^(3)×(2/3)^8 = 0.2384

The probability that the second fruit is an apple = ₁₁C₃×(1/4)^(3)×(3/4)^8 = 0.258

The probability that the third fruit is an apple = ₁₁C₃×(5/12)^(3)×(7/12)^8 = 0.16

The total probability = 0.2384 + 0.285 + 0.16 = 0.657

The number of ways in which the three can be selected = 3 × 2 × 1 = 6 ways

Therefore, the probability that the fruits will be selected in the order of banana then apple then orange = 0.657/6 = 0.1094.

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Step-by-step explanation:

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3 years ago
A quilt is made of 12 squares of equal size. Each square measures 15 cm by 15 cm.
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Answer:    12    x    15= 180 cuadrados

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Step-by-step explanation:

3 0
2 years ago
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Assume that an average cell has a diameter of
emmasim [6.3K]

Given that the volume of a cell is 50 cubic micrometers. It says to find the number of cells present in 1 cubic centimeter.

So we need to first convert the units of volume of a cell, then we can find the total number of cells in 1 cubic centimeter.

We know 1 meter = 100 centimeters = 1000000 micrometers

So 1 centimeter = 10000 micrometers

Taking Cubic powers on both sides :-

1 cubic centimeters = 10¹² cubic micrometers

1 cubic micrometers = 10⁻¹² cubic centimeters

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So volume of one cell = 5 × 10⁻¹¹ cubic centimeters

Number of cells = \frac{Total\;\; volume}{Volume\;\; of\;\; one\;\; cell}  = \frac{1\;cm^{3}}{5 * 10^{-11}\;cm^{3}} = \frac{10^{11}}{5} = 2 × 10¹⁰ cells.

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4 0
3 years ago
1. A gambler makes 100 column bets at roulette. The chance of winning on any one play is 12/38. The gambler can either win $ 5 o
lapo4ka [179]

Answer:

a) Expected amount of the gambler's win = $0.209

b) SD = 2.26

c)P (X >1) = P(z >0.35) = 0.36317

Step-by-step explanation:

The probability of winning, p = 12/38 =6/19

Probability of losing, q = 1 -p = 1-6/19

q = 13/19

Win amount = $5

Loss amount = $2

a) Expected total amount of win = ((6/19)*5) - ((13/19)*2)

Expected total amount of win = 1.579 - 1.369

Expected amount of win, E(X) = $0.209

b) Standard Deviation for the total amount of the gambler's win

SD = \sqrt{E(X^{2}) - (E(X))^{2} }

E(X²) = (6/19)*5²  -  (13/19)*2²

E(X²) = 5.158

SD = \sqrt{5.158 - 0.209^2}

SD = 2.26

c)  probability that, in total, the gambler wins at least $1.

P(X >1)

z = \frac{X - \mu}{\sigma}

μ = E(x) = 0.209

z = (1-0.209)/2.26

z = 0.35

P( X >1) = P(z >0.35)

P(z >0.35) = 1 - P(z <0.35)

P(z >0.35) = 1 - 0.63683

P(z >0.35) = 0.36317

5 0
3 years ago
Based on the box-and-whisker plot shown below, match each term with the correct value.
Katena32 [7]

Answer:

The table shows values for Variable A and Variable B.

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Variable B 18 22 19 7 24 16 17 20 20 23 17 25 21 18 15

Use the data from the table to create a scatter plot.

Step-by-step explanation:

4 0
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