Question

Plz help give brainliest

Answer 1

The equation $ax^2+bx+c=0$ has it's solutions given by $x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}$. This is the quadratic formula.

Looking at your equation we see a=1; b=-3 and c=-6 so by the quadratic formula,
$x = \frac{-(-3) \pm \sqrt{(-3)^2-(4 \times 1 \times -6)}}{2 \times 1} = \frac{3 \pm \sqrt{9+24}}{2}$

I'm sure you can work out what 9+24 is and so find the correct option :)