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tangare [24]
3 years ago
14

Plz help give brainliest

Mathematics
1 answer:
Lelu [443]3 years ago
8 0
The equation ax^2+bx+c=0 has it's solutions given by x= \frac{-b \pm \sqrt{b^2-4ac}}{2a}. This is the quadratic formula.

Looking at your equation we see a=1; b=-3 and c=-6 so by the quadratic formula,
x = \frac{-(-3) \pm \sqrt{(-3)^2-(4 \times 1 \times -6)}}{2 \times 1} = \frac{3 \pm \sqrt{9+24}}{2}

I'm sure you can work out what 9+24 is and so find the correct option :)
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