F(3) = 5 [5-3=2 diff]
f(4) = 8 [8-4=4 diff] (or 2 times larger than f(3)’s diff)
If that holds true, then continue the pattern:
f(5) = 13 [2 times f(4) diff = 8 so 5 + 8 = 13]
f(6) = 22
f(7) = 39
f(8) = 72
The only problem with my answer is that it could be times 2 or ^2. My answer above assumes times 2.
The surface area not including the top of the pool would be 748 ft(not sure if the teacher want you to add square to the end of it or not) .so 12*5 is 60 ,*2 =120. 24*5 =120. 120*2= 240. 24*12=288. so 288+240+120=748 ft(this would be the surface area of the pool.so if you need the volume of concrete needed to make the pool times the needed with of the concrete by the area ∆make sure if the needed thickness needed is in inches turn the area from feet to inches by multiplying it by 12 )
B because I took the test